Hydraulic Pump Closing a Floodgate

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The discussion centers on calculating the pressure exerted on a floodgate by a hydraulic cylinder and determining the horsepower of the pump needed for operation. The pressure on the floodgate is calculated to be approximately 2287 psi based on the force required and the area of the gate. However, the horsepower calculation is complicated by the lack of information regarding the pump's RPM, which is essential for determining power requirements. Without a specified closing speed for the floodgate, any pump with sufficient power could theoretically operate, but larger pumps would achieve faster closure. The conversation highlights the importance of pump speed in horsepower calculations while confirming the pressure exerted on the floodgate.
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Homework Statement


-4" hydraulic cylinder/piston
-closing a floodgate 4" in diameter, must exert force F=30,000lb to do so.
-Piston stroke is 2'.
-Hydraulic fluid specific gravity of 0.9.
-Pump efficiency of 0.8

Find A) the pressure on the floodgate and B) the horsepower of the pump.

Homework Equations


Pressure = Force/Area


The Attempt at a Solution


A) was trivial; the area of the gate is 4"=0.33ft, so Pi*r^2=0.087ft^2.
30,000lb/0.087sqft = 343,774 lb/sqft, or equivalent 2287 psi.

B) is baffling me, though, because the RPM of the pump is not given, and every equation I'm aware of for calculating horsepower requires the speed of the pump.
 
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I assume that the cylinder is stroking in the direction to extend the rod. If not, then your area is smaller.

If they don't tell you how fast they want the gate closed, then a pump of any power rating will work. Bigger pumps will close it quicker.
 
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