Integral by Trig Substitution, Calc 2

Darkestsolrac
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Homework Statement


The definite integral of ∫(x^2 √(a^2-x^2) dx from 0 to a


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The Attempt at a Solution



So i don't need actual help with this problem. I got the answer, (π*a^4)/16 and I verified with the back of the book. The question I have is whether this problem merits an entire side of work? None of the examples my professor has given have ever been more than a few lines of work and this took me a whole side of a paper. Am I being inefficient or should I just expect this from now on?

Oh and sorry if my notation bad or if this should be on another thread, this is my first post lol .__.
 
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I guess it amounts to how much you write. It requires a trig substitution followed by a double angle formula. Is that how you did it? Did you carry the limits along with the substitution or did you back substitute to x? That takes more steps. I used about 1/2 of one side of a standard sheet of paper for it.
 
I decided to back substitute into x, i thought converting the limits would be a hassle on this question. I think my issue was getting a sin4θ and not knowing any quick identities to simplify. Oh well, thanks for the response
 
You could have changed the integration limits after substitution. If you substituted x/a=sin(u) then the integral with respect to u goes from 0 to pi/2.

ehild
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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