- #1
player1_1_1
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Homework Statement
[tex]\int\limits_Ce^{\frac{1}{z^2}}\mbox{d}z[/tex] where [tex]C[/tex] is circle [tex]|z|=2[/tex]
The Attempt at a Solution
[tex]\sum\limits^{\infty}_{j=0}\frac{z^{-2j}}{j!}=1+\frac{1}{z^2}+\frac{1}{2!z^4}+\ldots[/tex]
[tex]I=2\pi ic_{-1}=2\pi i[/tex]
correct?