Integration by Parts Evaluate the integral

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Homework Help Overview

The discussion revolves around evaluating the integral ∫te^(-9t) dt using integration by parts, specifically applying the formula ∫udv = uv - ∫vdu. Participants are exploring the correct setup and execution of this method.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the choice of u and dv in the integration by parts setup, with some questioning the origin of constants in the expressions. There are attempts to clarify the integration process and identify errors in previous calculations.

Discussion Status

Some participants have offered tips on simplifying the integral before proceeding, while others have pointed out potential mistakes in the manipulation of constants. There is ongoing exploration of the correct final expression, with suggestions to verify results through differentiation.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the amount of direct assistance provided. There is a focus on understanding the integration process rather than simply obtaining the final answer.

emmaerin
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Homework Statement



Evaluate the integral. (Use C for the constant of integration.)

∫te ^ (-9t) dt

Homework Equations



∫udv = uv - ∫vdu

u=t dv= e ^ (-9t) dt
du=dt v=(-1/9) e ^(-9t)

The Attempt at a Solution



= -1/9 te^(-9t) - ∫-1/9 e ^(-9t) dt

Second Integral:
w=-9t
dw=-9dt
-81∫-1/9 * -81 e ^(-9t) dt
-81∫e^w * w
-81 * e^(-9t) +C

Final Answer:
= -1/9 te^(-9t) + 81 e ^(-9t) +C

This answer isn't right and I'm not sure where I'm going wrong, so any help would be appreciated. Thanks!
 
Last edited:
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A tip which has helped me is to always extract as much as possible before doing the integral. Doing that, you can see that it is actually the same integral as before, e^-9t. The error is simply that you multiplied with 81,while you should have divided.
 
emmaerin said:

Homework Statement



Evaluate the integral. (Use C for the constant of integration.)

∫te ^ (-9t) dt


Homework Equations



∫udv = uv - ∫vdu

u=t dv= (-1/9) e ^(-9t)
du=dt v=e ^ (-9t) dt
Where did that "-1/9" come from in "dv"?
The integral you are given is \int te^{-9t}dt. Writing that as \int u dv, you could take u= t, dv= e^{-9t}.

Or you could write the integral as -9\int t(-(1/9)e^{-9t})dt and then take dv= (-1/9)e^{-9t}dt but you don't seem to have done that.

The Attempt at a Solution



= -1/9 te^(-9t) - ∫-1/9 e ^(-9t) dt

Second Integral:
w=-9t
dw=-9dt
-81∫-1/9 * -81 e ^(-9t) dt
-81∫e^w * w
-81 * e^(-9t) +C

Final Answer:
= -1/9 te^(-9t) + 81 e ^(-9t) +C

This answer isn't right and I'm not sure where I'm going wrong, so any help would be appreciated. Thanks!
 
HallsofIvy said:
Where did that "-1/9" come from in "dv"?

You're completely right - I accidentally switched v and dv, thanks for pointing that out!
 
Sir Beaver said:
A tip which has helped me is to always extract as much as possible before doing the integral. Doing that, you can see that it is actually the same integral as before, e^-9t. The error is simply that you multiplied with 81,while you should have divided.

So is the final answer -1/9 t e ^(-9t) + 1/81 e ^(-9t) + C ?
 
emmaerin said:
So is the final answer -1/9 t e ^(-9t) + 1/81 e ^(-9t) + C ?


Differentiate it and see if you get your integrand.
 

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