Integration of multiple exponentials

Mzzed
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Homework Statement


I am struggling with solving this integral that seems to look easy on the surface but integration isn't my strong suit and so I'm not 100% sure on how to go about solving this:

∫ (120(e-15.24t - e-39984.75t))2dt

where the integration is from 0 to 0.3

Homework Equations

The Attempt at a Solution


I have tried using substitution for everything within the squared brackets and moved the 1202 outside of the integral. However this only seemed to make the question longer but that may simply be because I am not familiar with some techniques that I may have forgotten. This is not a homework question so any answers would be helpful.
 
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Mzzed said:

Homework Statement


I am struggling with solving this integral that seems to look easy on the surface but integration isn't my strong suit and so I'm not 100% sure on how to go about solving this:

∫ (120(e-15.24t - e-39984.75t))2dt

where the integration is from 0 to 0.3

Homework Equations

The Attempt at a Solution


I have tried using substitution for everything within the squared brackets and moved the 1202 outside of the integral. However this only seemed to make the question longer but that may simply be because I am not familiar with some techniques that I may have forgotten. This is not a homework question so any answers would be helpful.
Moving out 1202 is a good step, but substitution does not make the integration easier. Expand (e-15.24t - e-39984.75t)2, you get three exponents, easy to integrate.
 
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Gahh see I always overlook the simple things hahah thankyou
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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