Integration sines and cosines question

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The discussion focuses on integrating the product of sin(3x) and cos(4x) from -π to π, aiming to express these functions in exponential form. The correct exponential forms are sin(x) = (e^(ix) - e^(-ix))/(2i) and cos(x) = (e^(ix) + e^(-ix))/2, which were initially misrepresented. Participants suggest using trigonometric reduction formulas to simplify the integration process. The integral of sin(3x)cos(4x) over the specified limits is confirmed to equal zero. The conversation emphasizes the importance of accurately applying the exponential forms in the integration process.
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Express the sines and cosines in exponential form and integrate to show that (integral from -pi to pi) sin(3x)cos(4x)dx=0

What I'm thinking is that I should use sin x=e^x-e^-x/2 and cos x=e^x+e^-x/2. And I should multiply sin times 3 and cos times 4 and integrate. And get something like this:

(e^3pi+e^-3pi/2 * e^4pi-e^-4pi/2) - (e^-3pi+e^3pi/2 * e^-4pi-e^4pi/2)=0

I don't think this is right though. Can someone help please?
 
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Try looking up and using some trig reduction formulas.

cookiemonster
 
Yes, I would be inclined to use "reduction formulas" but if the problem specifically said "Express the sines and cosines in exponential form", then the way ilikephysics is approaching this is correct.

However, the formulas are wrong!

sin(x)= \frac{e^{ix}-e^{-ix}}{2i}
cos(x)= \frac{e^{ix}+e^{-ix}}{2}

ilikephysics forgot the "i"s.
 
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