Integration: Solve x^2-3x+2 Over x+1

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Homework Statement



Int(x^2-3x+2)/(x+1)dx



Homework Equations





The Attempt at a Solution



I don't know where to start.
 
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Start by dividing the two polynomials. The resultant expression will be much simpler.
 
kingdomof said:

Homework Statement



Int(x^2-3x+2)/(x+1)dx



Homework Equations





The Attempt at a Solution



I don't know where to start.

Instead of trying to factor simply divide it into 3 different equations i.e.


\int \frac{x^{2}}{x+1}dx - \int \frac{3x}{x+1}dx + \int \frac{2}{x+1}dx
 
djeitnstine said:
Instead of trying to factor simply divide it into 3 different equations i.e.


\int \frac{x^{2}}{x+1}dx - \int \frac{3x}{x+1}dx + \int \frac{2}{x+1}dx
These aren't equations: they are expressions.

A much simpler approach is to do as jgens advised, and divide x^2 - 3x + 2 by x + 1, using long division.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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