Is my Centroid Calculation Correct?

AI Thread Summary
The discussion revolves around the calculation of the centroid for a specific shape and whether it aligns with the horizontal line of equal area. Participants confirm that symmetry supports the assertion that the centroid lies on the same horizontal line as the line of equal area. A discrepancy arises when one user calculates the plastic modulus (Zp) and arrives at a different answer than the provided solution, prompting questions about the method used. Clarifications suggest that the book's answer may refer to the elastic section modulus rather than the plastic section modulus. Ultimately, understanding the differences in these concepts is crucial for accurate calculations.
fonseh
Messages
521
Reaction score
2

Homework Statement


For this shape , it's clear that the centroid and the horizontal line of equal axis lies on the same horizontal line , am i right ?

Homework Equations

The Attempt at a Solution


I'm not sure . correct me if i am wrong . [/B]
 

Attachments

  • 23.PNG
    23.PNG
    1.8 KB · Views: 775
Physics news on Phys.org
fonseh said:

Homework Statement


For this shape , it's clear that the centroid and the horizontal line of equal axis lies on the same horizontal line , am i right ?

Homework Equations

The Attempt at a Solution


I'm not sure . correct me if i am wrong . [/B]
Do you mean "line of equal area"?
Anyway, yes, symmetry should convince you that you're right if there's no other information given.
 
  • Like
Likes fonseh
Mark44 said:
Do you mean "line of equal area"?
Anyway, yes, symmetry should convince you that you're right if there's no other information given.
Are you familiar with plastic analysis ? Zp here is the plastic modulus .

I use another method to do , but i get different answer , why ?

Here's my working : , Zp = Sum of area x ( difference between centroid of particluar area and the equal area axis )

Zp = [ (130)(20)(150-10) + (150)(20)(150/2) ] x 2 = 1178000 , but the ans provided is only 929040
 
fonseh said:
Are you familiar with plastic analysis ?
No, I'm not, but I am familiar with the concept of centroids.
My answer is based on the fact that the shape in the drawing is symmetric about its horizontal midline.
fonseh said:
Zp here is the plastic modulus .

I use another method to do , but i get different answer , why ?

Here's my working : , Zp = Sum of area x ( difference between centroid of particluar area and the equal area axis )

Zp = [ (130)(20)(150-10) + (150)(20)(150/2) ] x 2 = 1178000 , but the ans provided is only 929040

If you had a rectangular piece of some uniform, rigid material 150 mm by 300 mm, its centroid would be at the center of the piece, at a point 75 mm to the right of the left edge, and 150 mm above the lower edge. If you cut out a rectangle 130 mm by 260 mm to form a "C" shape as in your drawing, the centroid of the piece you remove would be at its center, and the centroid of the remaining C-shaped piece would be along the horizontal midline, but a bit right of where it was for the original uncut piece of material.
 
Your number looks correct for the plastic section modulus perhaps the book is looking for the elastic section modulus you'll have to run the numbers
 

Similar threads

Replies
9
Views
2K
Replies
2
Views
2K
Replies
3
Views
2K
Replies
2
Views
2K
Replies
1
Views
3K
Replies
4
Views
2K
Replies
1
Views
10K
Back
Top