Is Object Acceleration Affected on a Frictionless Tabletop? | Expert Insights

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An object on a frictionless tabletop will experience acceleration when a force is applied. If the object is pushed with a constant force, it will maintain constant acceleration. Once the force is removed, the object will stop accelerating. The discussion emphasizes the importance of understanding the relationship between force and acceleration in a frictionless environment. This concept is crucial for solving related physics problems effectively.
Neek 007
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Obviously the question isn't easy to me, but anyway onwards with the question.

Can I assume an object has no acceleration if it is pushed on a frictionless tabletop?

This isn't a homework problem, its just going to help me solve my homework problem.
 
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Hi Neek 007! :smile:

While you push it, it accelerates.

Immediately you stop pushing, it stops accelerating. :wink:
 
oops i meant constant acceleration instead of no acceleration, sorry.
 
If it is pushed with constant force (which is actually fairly difficult to achieve), then yes it will have constant acceleration. :smile:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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