influx
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I used the formula Qin-Qout=Wnet and therefore had:
100-Qout =20 , so Qout=80 J..
They got -80J and I got 80J but is my answer still correct?
Yes, your answer is correct. But recognize that, by sign convention, heat flows in are considered positive and heat flows out are considered negative.influx said:![]()
I used the formula Qin-Qout=Wnet and therefore had:
100-Qout =20 , so Qout=80 J..
They got -80J and I got 80J but is my answer still correct?
Chestermiller said:Yes, your answer is correct. But recognize that, by sign convention, heat flows in are considered positive and heat flows out are considered negative.
Chet
A closed system is one in which mass neither enters nor leaves. This is the case for the system you are looking at.influx said:Thanks.
The first law of thermodynamics applies only to closed systems (not to open systems), but it also applies to cycles.. I'm confused as to what the relationship between cycles and closed systems is? Are cycles a type of closed system? My lecturer's notes are terribly confusing.
influx said:Thanks.
The first law of thermodynamics applies only to closed systems (not to open systems), but it also applies to cycles.. I'm confused as to what the relationship between cycles and closed systems is? Are cycles a type of closed system? My lecturer's notes are terribly confusing.
Chestermiller said:Yes, your answer is correct. But recognize that, by sign convention, heat flows in are considered positive and heat flows out are considered negative.
Chet
Work done by the system on the surroundings is considered positive.influx said:What about work? Does the above rule also apply for work flows? (i.e. is work flow in considered positive and work flow out considered negative)
Thanks
Chestermiller said:Work done by the system on the surroundings is considered positive.
Chet
influx said:What about work? Does the above rule also apply for work flows? (i.e. is work flow in considered positive and work flow out considered negative)
Thanks