Is the rise in mercury level due to a change in pressure or temperature?

AI Thread Summary
The discussion centers on the behavior of mercury in a tube when it is raised after sealing one end, leading to a rise in mercury level. The process is identified as not being adiabatic, as heat exchange occurs, and the pressure inside the tube decreases when the volume increases. There is debate over whether the transformation is isothermal, with some participants arguing that the system will eventually equilibrate to the original temperature. The consensus is that the mercury rises due to the pressure difference created by the change in volume. Ultimately, the system will reach thermal equilibrium with the surrounding environment.
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Homework Statement


A tube which is open at both ends is immersed in a beaker containing mercury. The top end which comes out of the mercury level is now sealed and then the tube is raised by some height such that some part still remains inside the beaker. The mercury inside the tube rises.
Which thermodynamic process takes place?
Why does the mercury inside the tube rise?

Homework Equations



none.

The Attempt at a Solution


Initially, let n be the number of moles of air inside the tube. Finally, the number of moles will be the same, since the air inside is sealed.
$$n=\frac{P_0V_0}{RT}$$
As the tube is raised, mercury level inside it rises. The process can't be adiabatic since heat excahange can take place. it could be isothermal but i don't know the exact reason.
As the tube is raised, the volume increases so pressure inside the gas decreases below ##P_0##, so the mercury level tends to move due to pressure difference.
 
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If you are asking whether this is a correct assessment, then yes, it is. You are also correct about the system not being adiabatic so that, when the system re-equilibrates, the temperature will again be the same as the original temperature.

Chet
 
Chestermiller said:
the temperature will again be the same as the original temperature.

Chet
Excuse me but, then, is it an isothermal transformation? I think that when we move the tube, the other end immersed exchanges heat, due to friction, with ambient that keeps temperature constant.
 
Pierce610 said:
Excuse me but, then, is it an isothermal transformation? I think that when we move the tube, the other end immersed exchanges heat, due to friction, with ambient that keeps temperature constant.
This makes no sense to me. Irrespective of what happens along the way, if you wait long enough, the system will come to equilibrium with the room temperature (i.e., the original temperature).

Chet
 
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