What is the Temperature at which the Gap Between Two Bars will be Closed?

AI Thread Summary
To determine the temperature at which a gap of 1.3x10^-3 m between a brass bar and an aluminum bar will close, the coefficients of linear expansion for both materials are essential. The equation ΔL = αLoΔT is used, where ΔL represents the change in length, α is the coefficient of linear expansion, Lo is the original length, and ΔT is the change in temperature. The total expansion of both bars must equal the gap, leading to the equation 1.3x10^-3 = (19x10^-6 * 2.0 + 23x10^-6 * 1.0)ΔT. Solving this gives a temperature increase of 21.3°C, resulting in a final temperature of 49.3°C when the bars will touch. This method effectively addresses the problem of thermal expansion in different materials.
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Homework Statement



A brass bar and an aluminium bar are each attached opposite each other to immovable walls. (There is a diagram, but I think the idea is clear enough). There is a gap between the two bars of 1.3x10-3m at 28°C.

At what temperature will the gap be closed?

coefficient of linear expansion of brass = 19x10-6 (C°)-1
aluminium = 23x10-6 (C°)-1

Length of brass bar = 2.0m
Length of aluminium bar = 1.0m

Homework Equations



ΔL = \alphaLoΔT

The Attempt at a Solution



I'm not sure where to begin really. Obviously part of the problem is that the two rods are not going to meet in the middle as they expand.

I have 2 unknowns for both rods in the equation for linear expansion, so it's not really helpful to rearrange for ΔT and set them equal to each other.

If you could get me started that would be great,

thanks!
 
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What must the sum of the ΔL's equal?
 
1.3 x 10^-3 m

Can I say:

ΔL + ΔL = \alphaLoΔT + \alphaLoΔT

1.3x10^-3 = (3.8x10^-5 + 23x10^-6)ΔT

ΔT = 21.3 degrees C

28 + 21.3 = Temp when bars will touch
 
Last edited:
BOAS said:
1.3 x 10^-3 m

Can I say:

ΔL + ΔL = \alphaLoΔT + \alphaLoΔT

1.3x10^-3 = (3.8x10^-5 + 23x10^-6)ΔT

ΔT = 21.3 degrees C

28 + 21.3 = Temp when bars will touch
I didn't check your arithmetic, but that is definitely the way to solve it.
 
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I'll check and double check.

Thanks a lot!
 
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