Why Does Concrete Contract Differently in Cold Temperatures?

AI Thread Summary
The discussion centers on a physics quiz question regarding the contraction of concrete due to temperature changes. The correct calculation involves using the coefficient of linear thermal expansion, which is 10^-5 per degree Celsius, and applying it to the temperature change from 24 °C to -16 °C, resulting in a change of -40 °C. The calculation yields a contraction of approximately 0.72 cm, which is close to the provided answer of 0.5 cm, suggesting possible rounding or unit conversion errors. Participants emphasize the importance of double-checking calculations and units to avoid mistakes. The conversation concludes with encouragement for future quizzes.
titusdna
Messages
2
Reaction score
0
Got this question wrong on this weeks physics quiz and can't figure out why. I keep getting the same answer - which was wrong - over and over. What am I missing?

By how much will a slab of concrete 18 m long contract when the temperature drops from 24 °C to -16 °C? (The coefficient of linear thermal expansion for concrete is 10-5 per degree C.)
Answers are in centimeters.
Formula:
change in length= a* Lo* change in temp
Lo = 1800cm
A = 10-5
change in T = 24- (-16) = 40
I keep coming up with .7 cm
the answer was .5cm
Where did I go wrong? Any help greatly appreciated
Thank you
 
Physics news on Phys.org
I can't find an error in your calculations. Maybe the result was rounded in the answers or there's a typo somewhere?
 
for reaching out for help with this question. It seems like you have the correct formula and values, so let's go through the steps to see where the error may have occurred.

First, let's check the units. The coefficient of linear thermal expansion is given in 10^-5 per degree C, so we need to make sure that our temperature change is also in degrees Celsius. In this case, 24 °C to -16 °C would be a change of -40 °C, not 40 °C.

Next, let's double check the calculation. Using the formula, we get:
change in length = (10^-5) * 1800cm * (-40 °C) = -0.72 cm
So it looks like the answer should be -0.72 cm, which is close to the answer you were getting. However, the question asks for the change in length in centimeters, so we need to take the absolute value of this answer. This gives us a final answer of 0.72 cm, which is closer to the given answer of 0.5 cm.

It's possible that there was a rounding error at some point in the calculations, or an incorrect unit conversion. Make sure to always double check your units and calculations to avoid any errors. I hope this helps and good luck on your future quizzes!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .

Similar threads

Back
Top