- #1

- 177

- 0

an electron with velocity u = (3,12,-4) x 10^5 experiences no net force at a point in a magnetic field B = ((10,20,30)/ Find E at that point.

I found the magnetic force by u cross B. Set Fe equal to Fm. Divided by q to get E = u cross B. but im not getting the same answer as the back of the book. just need a confirmation.

im getting E = (4.4 x 10^7, -1.3 x 10^7, -6 x 10^6)

the book has the same number for the x direction, its just 4400.

I found the magnetic force by u cross B. Set Fe equal to Fm. Divided by q to get E = u cross B. but im not getting the same answer as the back of the book. just need a confirmation.

im getting E = (4.4 x 10^7, -1.3 x 10^7, -6 x 10^6)

the book has the same number for the x direction, its just 4400.

Last edited: