Magnetism Question - Compare Radii of Circular Paths

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SUMMARY

The discussion focuses on comparing the radii of circular paths for a proton, a deuteron, and an alpha particle moving through a uniform magnetic field at right angles. The key equation used is v = qBR/m, which leads to the derived formula for kinetic energy: K = (q²B²R²)/2m. The relationship between the radius (R) and the mass (m), charge (q), and kinetic energy (K) is established, allowing for a definitive comparison of the radii based on these variables.

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[SOLVED] Magnetism question

Homework Statement



A proton, a deuteron and an alpha particle with the same kinetic energies enter a region of uniform magnetic field, moving at right angles to B. Compare the radii of their circular paths.

Homework Equations



v = qBR / m

The Attempt at a Solution



Using the equation above:
K (kinetic energy) = [(q^2)(B^2)(R^2)] / 2m
so (R^2) = (2mK) / [(q^2)(B^2)]
From here, I don't know what to do... How do I compare the radii?
 
Last edited:
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Never mind... got it.
 

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