Magnetron Electron Field Strength

AI Thread Summary
The discussion focuses on calculating the strength of a magnetic field based on a given resonant frequency and electron period of revolution. The key equations used include qvb = mv²/r and qb = mv/r, with the participant initially struggling to relate velocity and radius to the frequency and period. They clarify that the period represents the time taken for one complete revolution, leading to the derivation of velocity as the circumference divided by the period. Ultimately, the calculated magnetic field strength is approximately 0.5253 T. This solution highlights the importance of understanding the relationship between period, velocity, and radius in magnetic field calculations.
haxxorboi
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Homework Statement


Suppose the resonant frequency is f = 1.47×1010 s−1; that is, the electron period of revolution is T = 6.80×10-11 s. What is the corresponding strength of the magnetic field?


Homework Equations


qvb=mv2/r
qb=mv/r


The Attempt at a Solution


1.6E-19*b=9.1E-31*v/r

I understand the general idea, to figure out b, but I don't understand how to figure out Velocity or Radius from the frequency/period.

Can someone give me a point in the right direction?
 
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Hi haxxorboi,

haxxorboi said:

Homework Statement


Suppose the resonant frequency is f = 1.47×1010 s−1; that is, the electron period of revolution is T = 6.80×10-11 s. What is the corresponding strength of the magnetic field?


Homework Equations


qvb=mv2/r
qb=mv/r


The Attempt at a Solution


1.6E-19*b=9.1E-31*v/r

I understand the general idea, to figure out b, but I don't understand how to figure out Velocity or Radius from the frequency/period.

When they give the period, that is the period of what? In other words, if the period is 6.80×10-11 s, what happens every 6.80×10-11 seconds? Once you answer that, you should be able to write down an equation relating T, r, and v. What do you get?
 
alphysicist said:
Hi haxxorboi,

When they give the period, that is the period of what? In other words, if the period is 6.80×10-11 s, what happens every 6.80×10-11 seconds? Once you answer that, you should be able to write down an equation relating T, r, and v. What do you get?

Velocity=Distance/Time
Velocity=Circumference/Period
Velocity=2*Pi*R/6.8E-11 sec
Velocity=9.24E10R

1.6E-19*B=9.1E-31*(9.24E10R)/R

B=.5253 T


Thank you very much, that was killing me!
 
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