Magnetron Electron Field Strength

AI Thread Summary
The discussion focuses on calculating the strength of a magnetic field based on a given resonant frequency and electron period of revolution. The key equations used include qvb = mv²/r and qb = mv/r, with the participant initially struggling to relate velocity and radius to the frequency and period. They clarify that the period represents the time taken for one complete revolution, leading to the derivation of velocity as the circumference divided by the period. Ultimately, the calculated magnetic field strength is approximately 0.5253 T. This solution highlights the importance of understanding the relationship between period, velocity, and radius in magnetic field calculations.
haxxorboi
Messages
24
Reaction score
0

Homework Statement


Suppose the resonant frequency is f = 1.47×1010 s−1; that is, the electron period of revolution is T = 6.80×10-11 s. What is the corresponding strength of the magnetic field?


Homework Equations


qvb=mv2/r
qb=mv/r


The Attempt at a Solution


1.6E-19*b=9.1E-31*v/r

I understand the general idea, to figure out b, but I don't understand how to figure out Velocity or Radius from the frequency/period.

Can someone give me a point in the right direction?
 
Physics news on Phys.org
Hi haxxorboi,

haxxorboi said:

Homework Statement


Suppose the resonant frequency is f = 1.47×1010 s−1; that is, the electron period of revolution is T = 6.80×10-11 s. What is the corresponding strength of the magnetic field?


Homework Equations


qvb=mv2/r
qb=mv/r


The Attempt at a Solution


1.6E-19*b=9.1E-31*v/r

I understand the general idea, to figure out b, but I don't understand how to figure out Velocity or Radius from the frequency/period.

When they give the period, that is the period of what? In other words, if the period is 6.80×10-11 s, what happens every 6.80×10-11 seconds? Once you answer that, you should be able to write down an equation relating T, r, and v. What do you get?
 
alphysicist said:
Hi haxxorboi,

When they give the period, that is the period of what? In other words, if the period is 6.80×10-11 s, what happens every 6.80×10-11 seconds? Once you answer that, you should be able to write down an equation relating T, r, and v. What do you get?

Velocity=Distance/Time
Velocity=Circumference/Period
Velocity=2*Pi*R/6.8E-11 sec
Velocity=9.24E10R

1.6E-19*B=9.1E-31*(9.24E10R)/R

B=.5253 T


Thank you very much, that was killing me!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top