- #1

- 186

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So we use the following equations:

[tex] v_{y} = v_{y0} -gt [/tex]

[tex] y-y_0 = v_{y0}t - \frac{1}{2}gt^{2} [/tex]

[tex] y-y_0 = \frac{1}{2}(v_{y0} + v_y)t [/tex]

[tex] v_{y}^{2} = v_{y0}^{2} - 2g(y-y_0) [/tex]

So we probably have to consider 2 cases: the elevator and the marble.

__Elevator__[tex] v_y = v_{y0} [/tex]

[tex] y = v_{y0}t [/tex]

[tex] y = \frac{1}{2}v_{y}t [/tex]

[tex] v_{y}^{2} = -2g(y-y_0) [/tex]

Am I on the right track?