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lucky_star
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Homework Statement
If 100 g H2O contains 11.2 g H, what mass of water could be obtained from 3.06 g H2(g) reacting with an excess of O2(g)?
Homework Equations
Mass % of X in a sample= (Mass of X in sample/ Mass of the sample)*100
The Attempt at a Solution
The parts that confused me were 11.2g of H and the 3.06g H2. Why aren't both be H2 or H? Can anyone help me with this problem? THank you in advance.
This is my effort:
I look for the mass fraction of H in 100g of H2O:
11.2g of H/100g H2O= .112
Then, I find the Mass of H2O
3.06g/.112 = 27.3g H2O
Is this correct?