Mass of Planet Using Radius and Doppler Effect

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SUMMARY

The discussion focuses on calculating the mass of a distant planet based on the radius of a spacecraft's orbit and the Doppler effect observed in its radio signal. The user initially calculated the mass using the formula M = (rv²)/G, with G = 6.67×10-11 m3 kg-1 s-2 and r = 128,000 km. The user derived a mass of approximately 2.48×1018 kg but received an incorrect result due to unit conversion errors, specifically not converting kilometers to meters. The correct approach requires consistent unit usage for accurate calculations.

PREREQUISITES
  • Understanding of gravitational force and orbital mechanics
  • Familiarity with the Doppler effect and its application in astronomy
  • Proficiency in unit conversion, particularly between kilometers and meters
  • Knowledge of the formula M = (rv²)/G for calculating mass
NEXT STEPS
  • Review unit conversion techniques in physics, especially for gravitational calculations
  • Study the Doppler effect in detail, focusing on its implications in astrophysics
  • Explore the relationship between orbital radius and velocity in circular motion
  • Learn about gravitational constants and their applications in celestial mechanics
USEFUL FOR

Astronomy students, astrophysicists, and anyone interested in gravitational calculations and the application of the Doppler effect in determining planetary masses.

Linuxkid
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Homework Statement


Imagine you are observing a spacecraft moving in a circular orbit of radius 128,000 km around a distant planet. You happen to be located in the plane of the spacecraft 's orbit. You find that the spacecraft 's radio signal varies periodically in wavelength between 2.99964 m and 3.00036 m. Assuming that the radio is broadcasting normally, at a constant wavelength, what is the mass of the planet?


Homework Equations


M= \displaystyle{\frac{rv^2}{G}}; \space<br /> <br /> where \space G= 6.67\times10^{-11} \space m^3 kg^{-1} s^{-2},<br /> <br /> \space r \space is \space km, \space and \space v \ is \space<br /> km/s <br />



The Attempt at a Solution



Well, as we have a change in wavelength 2.99964 m and 3.00036 m respectively, the original signal should equal 3.00000m. With the formula from my textbook ( "Astronomy" 6th edition by Chaisson and McMillan, page 63), \frac{apparent\space \lambda}{true \space \lambda} -1 = speed \space in \space c Then I multiply it by c and convert meters to kilometers and get\approx 36 km/s.

I input r and G as G= 6.67\times10^{-11} \space m^3 kg^{-1} s^{-2}, \space r= 128, 000 km.


So: M= \displaystyle{\frac{(128000km)*(36 km/s)^2}{6.67\times 10^{-11}\space m^3 kg^{-1} s^{-2}}} = 2.48\times10^{18} kg.


When I input this answer into the website in which we do our homework by, it gives me a lousy red X. I'm sure I messed up, because I was expecting a planet approximately in the 10^20-28 kg range.


Regardless, I've been stuck on this for a bit. Help is much appreciated.





Nikos
 
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Check your units, I think you are not converting km to m.
 
possibly you are using different values for your constants, or you have rounded off differently?
[edit]ah - your value for G has length in meters.
 
Hey there,


Aha! I missed that my constant was in meters.



Honest mistake. Thanks a lot.
 

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