Max Height & Initial Speed Calculation | Bottle Rocket Lab Help

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To calculate the maximum height and initial speed of a bottle rocket, the total flight time of 6.52 seconds is utilized. The maximum height is derived using the equation d = 1/2gt^2, resulting in a height of 52.1 meters. The initial speed is calculated with v = (-9.80 m/s^2)(6.52 s)/-2, yielding 31.9 m/s. There is uncertainty regarding the application of significant figures in these calculations. Clarification on the calculations and significant figures is requested before the assignment deadline.
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Homework Statement


Calculate the maximum height and the initial speed of the rocket. Show The equaltions and then show your substitutions. The total flight time was 6.52 seconds. the height time will be expressed in meters and feet and the velocity will be expressed at m/s, feet/second, miles/hour, km/hour.


Homework Equations


d=1/2gt^2 - only when initial velocity is 0 and object is at free fall. So i would have to use
a=change in velocity/time
a=gravity
g = -v -(+v)/t ====> v = gt/-2

The Attempt at a Solution



d= h = 1/2(9.80m/s^2)(3.26s^2) = 52.1m - 3 sig figs when multiplying correct?

v= (-9.80m/s^2)(6.52s)/-2

v= 31.9m/s => again not sure on the significant figs part.

please tell me if i am doing this correctly. thank you very much
 
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