Max Mass of Block C to Slide Block A & B Together

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The discussion revolves around determining the maximum mass of block C that allows blocks A and B to slide together without separation. The user initially calculates the acceleration of the system and attempts to equate it to the maximum static friction force. However, confusion arises as they misinterpret the maximum static friction force as an acceleration. Participants clarify that the maximum acceleration should be derived from the static friction force divided by the total mass, leading to a reevaluation of the equations used. The user seeks further assistance to resolve the discrepancies in their calculations.
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Block B, of mass m_B, rests on block A, of mass m_A, which in turn is on a horizontal table top View Figure . The coefficient of kinetic friction between block A and the table top is mu_k and the coefficient of static friction between block A and block B is mu_s. A light string attached to block A passes over a frictionless, massless pulley and block C is suspended from the other end of the string.

http://session.masteringphysics.com/problemAsset/1007012/5/yf_Figure_5_66.jpg

What is the largest mass m_C that block C can have so that blocks A and B still slide together when the system is released from rest?

Okay, I get:

a = [m_c *g - (m_a + m_b)*g * mu_k]/(m_a + m_b)

and the max a is m_b * g * mu_s.

I set them equal, and end up with
m_c = (m_a + m_b)(mu_k + mu_s * m_b)

but that isn't correct. help?
 
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the max a is m_b * g * mu_s.
m_b * g * mu_s is a force, not an acceleration.
 
I'm stuck on the same problem. I get the same acceleration that you get, but for the Max Acceleration I get (mu_s * m_b * g) / m_b, and then i set them equal to each other, but I still get it wrong. There must be something I am overlooking.
 
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