Maximum Static Force before Blocks Slip

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SUMMARY

The discussion centers on calculating the maximum static force before two blocks begin to slip against each other. A 6.40kg block rests on a 12.5kg block, with a frictionless interface between the lower block and the table, while static and kinetic friction exist between the two blocks. The acceleration at which the blocks start to slip is 2.0 m/s². To find the force at the moment of slipping, one must first determine the normal force acting on the upper block and apply the static friction formula, fs = μsFN.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction coefficients (μs and μk)
  • Ability to calculate normal force in a multi-block system
  • Familiarity with basic physics equations related to force and acceleration
NEXT STEPS
  • Calculate the normal force acting on the upper block using FN = m*g
  • Research the relationship between static friction and maximum force before slipping
  • Explore the concept of friction in multi-body systems
  • Learn about dynamics and forces in two-dimensional motion
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of friction and motion in multi-block systems.

patchums
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An 6.40kg block rests on a 12.5kg block. The interface between the lower mass and the table is frictionless, but there is friction (static friction μs and kinetic friction μk) between the two blocks. A horizontal force F acts on the upper block and causes both blocks to accelerate. The acceleration of both blocks when they begin to slip is 2.0 m/s2.

fk=μkFN
fs=μsFN

I guess I have no idea how to start with this question. Am I supposed to find the normal force first and work from there? Where do I even go from there? Any help would be appreciated, thanks much!
 
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patchums said:
An 6.40kg block rests on a 12.5kg block. The interface between the lower mass and the table is frictionless, but there is friction (static friction μs and kinetic friction μk) between the two blocks. A horizontal force F acts on the upper block and causes both blocks to accelerate. The acceleration of both blocks when they begin to slip is 2.0 m/s2.

fk=μkFN
fs=μsFN

I guess I have no idea how to start with this question. Am I supposed to find the normal force first and work from there? Where do I even go from there? Any help would be appreciated, thanks much!

You haven't stated what it is you're trying to find...
 
Aw geez, sorry. I have to find the force at the time when the blocks start to slip.
 
patchums said:
Aw geez, sorry. I have to find the force at the time when the blocks start to slip.

Okay, so immediately before the blocks begin to slip they are essentially one large block...
 
Try to imagine by sitting on the lower block. What you see? Where should the force act?
 

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