Mean temperature of winding when current falls

AI Thread Summary
The discussion revolves around calculating the mean temperature of a winding when current decreases, using the resistance-temperature relationship. The initial calculations provided a resistance of 63.94 ohms, but the user struggled to derive the correct temperature. A key error was identified in the manipulation of the equation, particularly in the sequence of operations. After clarification, the user acknowledged the mistake and expressed gratitude for the assistance. The conversation emphasizes the importance of careful mathematical operations in solving physics problems.
DevonZA
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Homework Statement


upload_2016-5-1_12-0-27.png


Homework Equations


R2=R1(1+alpha(t2-t1))

The Attempt at a Solution


R1=250/5=50ohms
R2=250/3.91=63.94ohms

R2=R1(1+alpha15degrees(t2-t1))
63.94=50(1+1/254.5(t2-15))
t2=

Now I found this online but the answers provided still don't match, 84.25 being the closest.

upload_2016-5-1_12-12-12.png


When I manipulate the equation I get a totally different answer:
63.94=50(1+1/254.5(t2-15))
63.94/50=(1+1/254.5(t2-15))
1.2788/1+1/254.5=t2-15
1.274=t2-15
t2=1.274+15=16.274 degrees

Please help me understand where I am going wrong.
 
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DevonZA said:
where I am going wrong.
DevonZA said:
63.94/50=(1+1/254.5(t2-15))
1.2788/1+1/254.5=t2-15
upload_2016-5-1_12-12-12-png.100061.png

Is this from B.L. Theraja?
 
Not sure I found it online
 
DevonZA said:
Not sure I found it online
It is from B.L. Theraja. The page looks familiar. The red line in the above post is your error.
 
What have I done wrong though? Every way I enter it into my calculator yields an incorrect answer
 
DevonZA said:
63.94/50=(1+1/254.5(t2-15))
1.2788/1+1/254.5=t2-15[/\QUOTE]
This step is wrong. Check the sequence of operations.
 
Ah I got it :-) thank you
 
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