Hello,(adsbygoogle = window.adsbygoogle || []).push({});

I'm trying to come up with a method for calculating the mechanical advantage of a vehicle's suspension (i.e. how much does the spring compress if I move the wheel center by some infinitesimally small amount?). I have a method that I thought was correct, but I recently compared my calculations to results from a trusted software package and found that my numbers are off a bit. Can anyone spot an error in my theory or suggest what my pitfall might be?

I'm assuming that I'm working with a double A-arm suspension, which is essentially a 4-bar linkage. Attached to the lower A-arm is a pushrod (attached via a spherical bearing). This pushrod goes to a bellcrank (lever) that rotates around an axis. Also attached to this bellcrank are the spring and damper. So to compress the spring, the wheel must move up, which makes the lower control arm push on the pushrod, the pushrod makes the bellcrank rock on it's axis of rotation, and the other end of the bellcrank compresses the spring. I know all of the locations of the joints and the axis of rotation in 3-space. My method is this:

1. Find the equations of the planes that contain the upper and lower control arms.

2. The wheel's instantaneous axis of rotation must be the axis created by the intersection of those two planes. Find that axis.

3. Find the points on that axis that is closest to the wheel center and the location of the attachment between the pushrod and lower control arm.

4. Define a "virtual force" vector that points upwards to be applied to the center of the wheel.

5. The sum of the moments around the wheel's instantaneous axis of rotation must be zero. We can write this equation:

(Vector_from_wheel_center_to_axis) cross (virtual_force_vector) + (vector_from_pushrod_end_to_axis) cross (reaction_force_at_pushrod) = 0

Everything except the reaction at the pushrod is known.

6. We know the direction of the reaction force because the spherical bearing can't transmit torques (safe assumtion) - the force must be in the direction of the pushrod. We can re-write the equation:

(Vector_from_wheel_center_to_axis) cross (virtual_force_vector) + (vector_from_pushrod_end_to_axis) cross (magnitude_of_reaction_force * direction_of_reaction_force_at_pushrod) = 0

For more clarity, we re-write again:

Moment_due_to_virtual_force + (direction_of_reaction_moment * moment_arm_length) * magnitude_of_reaction_force = 0

7. Now the only unknown is the magnitude of the reaction force. I think it is safe to divide any of the three components (so long as they are non-zero) of the moment from the virtual force by the same component of the direction of the reaction moment times the moment arm length.

8. Knowing the force through the pushrod, we can use the same procedure above to find the moments around the bellcrank's axis of rotation, solving for the spring force at the end.

9. Because we applied a "virtual force" to the wheel, the force we see in the spring can be divided by the magnitude of the original "virtual force," and this ratio should not only be the ratio in the forces, but also the ratio in movement (say instead of a virtual force, we applied an infinitesimally small displacement).

Any help is appreciated! Can anyone see what I'm doing wrong or suggest a better way to solve the problem? If this is clear as mud, let me know and I'll try to post some pictures.

Thanks!

-Kerry

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Mechanical Advantage through series of links

Loading...

Similar Threads - Mechanical Advantage through | Date |
---|---|

Linear force > Angular torque > Mechanical advantage | Feb 6, 2016 |

Mechanical Advantage of a 4-bar | Nov 3, 2014 |

Elementary mechanical advantage question | Dec 2, 2012 |

Mechanical Advantage of a four bar linkage. | Feb 16, 2012 |

Mechanical advantage planetary gear help | Dec 13, 2009 |

**Physics Forums - The Fusion of Science and Community**