Motion of Charged Particles in Electric Fields

Thread starter simplicity12
Start date Apr 12, 2007
Tags

Charged Charged particles Electric Electric fields Fields Motion Particles

AI Thread Summary

The discussion centers on calculating the smallest distance between two electrons fired at each other at a speed of 3.5 x 10^6 m/s. The user attempts to equate kinetic energy (Ek) and electric potential energy (Ee) but is struggling to arrive at the correct answer. Clarification is sought on the physical representation of Ek, including the variables mass (m) and velocity (v). Participants are encouraged to provide detailed solutions to identify potential errors in the user's calculations. The conversation emphasizes the importance of understanding the relationship between kinetic and electric potential energy in this context.

Apr 12, 2007

simplicity12

Homework Statement

3. Two electrons are fired at 3.5 x 10^6 m/s directly at each other.
a)Calculate the smallest possible between the two electrons.

Homework Equations

Ek= 1/2mv^2
Ee= kq1q2/r

The Attempt at a Solution

I made the Ek and the Ee equal, but i keep on getting the wrong answer. Can someone please help me?

Physics news on Phys.org

Apr 12, 2007

robphy

Science Advisor

Homework Helper

Insights Author

Gold Member

What does Ek represent physically? (what is m? v?)

Apr 12, 2007

marcusl

Science Advisor

Please show us your work so we can point out where the error is.

Thread 'Rolling without slipping on a curved surface'

Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .

View full post »

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »