Falken_47
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Homework Statement
Suppose a proton is at rest and at the origin of some coordinate system. Then, electric field of E(r) = E0 X-hat is turned on. What is the position of proton at time t and then its velocity?
Homework Equations
E(r) = E0 X-hat
Fproton = e * E(r)
The Attempt at a Solution
By using, Fproton = e * E(r), I obtained
ma = e * E0 X-hat
a = ( ( e * E0 ) / m ) X-hat
therefore, integrating the equation, I obtained
v = ( ( e * E0 * t ) / m ) X-hat
x = ( ( e * E0 * t2 ) / ( 2 * m ) ) X-hat
(note that constant of integration is ignored because initial v and x is zero)
So, the above answer should be correct right? And when we graph it we would have a parabola for x and a line of constant slope for v which is then similar to the model of an object under constant acceleration?
I'm just making sure since the answer to the question is pretty much straightforward that I'm afraid I'm missing something.
Thank you in advance!