Motion problem -- Calculations given the v(t) graph of a person jumping

AI Thread Summary
The discussion revolves around a motion problem involving calculations based on a v(t) graph of a person jumping. The original poster seeks validation for their answers and expresses uncertainty about part b of the question. Respondents confirm that the calculations appear correct and suggest that square counting might be required, although it's deemed unlikely. Overall, the feedback reassures the poster that their work is solid. The conversation emphasizes the importance of accuracy in interpreting graphical data in motion problems.
shk
Messages
78
Reaction score
8
Homework Statement
I need someone to check my working for this question please.
Relevant Equations
a=v/t
Hi
I have answered the question and have attached my working .
I'm not very sure about part b. I generally need someone to check my working and let me know if I've made a mistake.
Thanks
 

Attachments

  • Screenshot_20201021-095044_WhatsApp.jpg
    Screenshot_20201021-095044_WhatsApp.jpg
    90.9 KB · Views: 141
  • 20201021_095342.jpg
    20201021_095342.jpg
    19.4 KB · Views: 140
Last edited by a moderator:
Physics news on Phys.org
Looks good. Since it is on graph paper, they might want you to do some square counting, but unlikely.
 
  • Like
Likes shk and Marso
Everything seems in order!
 
  • Like
Likes shk
haruspex said:
Looks good. Since it is on graph paper, they might want you to do some square counting, but unlikely.
Thanks for the comment 👍
 
Marso said:
Everything seems in order!
Thank you very much
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top