Newton's Law- 3 objects on a pulley

AI Thread Summary
The discussion centers on solving a physics problem involving three objects connected by strings over a pulley. The user attempts to calculate the acceleration and tension in the system but initially arrives at an incorrect acceleration of 9.8 m/s² instead of the expected 1.63 m/s². The error is identified as a mistake in the signs used in the equations, particularly regarding the direction of acceleration for the objects. After correcting the sign convention, the user successfully recalculates the acceleration as 1.6 m/s². This highlights the importance of accurately applying sign conventions in physics problems.
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Homework Statement



p4-62alt.gif


Three objects are connected by light strings as shown in Figure P4.62. The string connecting the m1 = 5.00 kg mass and the m2 = 4.00 kg mass passes over a light frictionless pulley.

a) find the acceleration of each object and
b) the tension in the two strings




Homework Equations



sumF = m*a

sumF1= m1*a = T1 - m1*g
sumF2= m2*a = T1 - m2*g - T2
sumF3= m3*a = T2 - m3*g



The Attempt at a Solution



I combined equations sumF1 and sumF2:

m1*a = T1 - m1*g
-m2*a = -T1 + m2g +T2

to get rid of one variable, T1, and I got

m2*g - m1*g + T2 = m1a - m2a

then in the sumF3 equation I solved for T2,
T2 = m3*a + m3*g

and plugged that into the above equation to get
m2*g - m1*g + (m3*a + m3*g) =m1*a - m2*a

I then plugged in my knowns to get 9.8 m/s/s, while the answer is supposed to be 1.63 m/s/s.

Can anyone please help? Where did I go wrong? I thought I understood this..
 
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johnsonandrew said:

Homework Statement



p4-62alt.gif


Three objects are connected by light strings as shown in Figure P4.62. The string connecting the m1 = 5.00 kg mass and the m2 = 4.00 kg mass passes over a light frictionless pulley.

a) find the acceleration of each object and
b) the tension in the two strings




Homework Equations



sumF = m*a

sumF1= m1*a = T1 - m1*g
sumF2= m2*a = T1 - m2*g - T2
sumF3= m3*a = T2 - m3*g



The Attempt at a Solution



I combined equations sumF1 and sumF2:

m1*a = T1 - m1*g
-m2*a = -T1 + m2g +T2

to get rid of one variable, T1, and I got

m2*g - m1*g + T2 = m1a - m2a

then in the sumF3 equation I solved for T2,
T2 = m3*a + m3*g

and plugged that into the above equation to get
m2*g - m1*g + (m3*a + m3*g) =m1*a - m2*a

I then plugged in my knowns to get 9.8 m/s/s, while the answer is supposed to be 1.63 m/s/s.

Can anyone please help? Where did I go wrong? I thought I understood this..
you're on track, but the stuff on the left accelerates up, and the stuff on the right acceleartes with the same magnitude, except it accelerates down, You've slipped up on your plus and minus signs.
 
Ohh. I was wondering about that. So on the right side down would be positive if I took up to be positive on the left?
 
johnsonandrew said:
Ohh. I was wondering about that. So on the right side down would be positive if I took up to be positive on the left?
Yes, that should work.
 
Ahhh and it did. It gave me 1.6! Thanks a lot!
 
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