m1 = 1,378 g. It is free to move along a horizontal, frictionless surface. This block is connected to a second block with mass of m2 = 872 g by a massless string that extends around a massless, frictionless pulley. Find the tension of the string.
F net = ma since the system is not at equilibrium.
The Attempt at a Solution
So for m1,
Tension (T) = 1.378 kg*a.
mg-T = m2*a
T = 8.55 N - 0.827 kg*a
since tension is equal at any point along the string, i equated both equations and isolate acceleration;
1.378 kg*a = 8.55 N - 0.872 kg*a
a = 3.8 m/s^2.
therefore T = 1.378 kg * 3.8 m/s^2 = 5.24 N.
did i approach this question properly?
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