Oscillation Frequency for Peak Voltage

AI Thread Summary
The discussion centers on calculating the oscillation frequency for peak voltage in a loop of wire, where the key equation is E(max) = NABw = 2pi*NABf. The user struggles to determine the variable N, which represents the number of turns in the wire loop. It is clarified that since the problem specifies "a loop of wire," N equals 1. Additionally, an alternative approach using the laws of electromagnetism is suggested for deriving the equation without needing to know N. Understanding these concepts can enhance confidence in solving similar problems.
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Homework Statement



Here is the prompt:

http://i.imgur.com/GsZck8J.jpg


Homework Equations



E(max) = NABw = 2pi*NABf

The Attempt at a Solution



E(max) = NABw = 2pi*NABf
= NA*B(nought)*2pi*f
1.50 / (NA*B(nought)*2pi) = f
f = 1.50 / N / ((2.50/100)^2*pi) / 0.109 / (2pi)

The problem I'm having is I don't know how to figure out N because it is not given, and I don't know any other equations that exclude the N variable.
 
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I suspect they have told you what N is.
What does N stand for in that equation?
 
N is the number of turns, and I suppose since this isn't a solenoid that N=1
 
That's the one - the problem statement specifically says "A loop of wire..." - that would be 1.

You could also have got there by applying the Laws of electromagnetism instead of trying to memorize specific results. Then you'd just derive an equation that never has an N in it... you'd feel more confident about the result too, but it would take a lot longer ;)
 
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