Parallel flow pipe network help

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SUMMARY

The discussion focuses on solving a parallel flow pipe network problem where the flow is pressurized and returns to a negligible piping system. The key equations established include the flow conservation equation Q = Q1 + Q2 and the head loss equality for both pipes. The friction factor, crucial for calculating head loss, can be determined using the Swamee and Jain formula, which relies on the Reynolds Number. The participants explore methods to avoid iterative calculations for friction factors and discuss deriving total pressure loss in the system using loss coefficients.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically flow conservation.
  • Familiarity with head loss calculations in pipe systems.
  • Knowledge of the Swamee and Jain formula for friction factor determination.
  • Basic concepts of Reynolds Number and its significance in flow analysis.
NEXT STEPS
  • Research methods to calculate friction factors without iterative processes, such as using empirical correlations.
  • Explore advanced fluid dynamics simulations using software like ANSYS Fluent for complex pipe networks.
  • Learn about loss coefficients and their impact on pressure drop calculations in piping systems.
  • Study the application of Bernoulli's equation in analyzing pressure loss across different pipe configurations.
USEFUL FOR

Engineers, fluid dynamics specialists, and anyone involved in the design or analysis of piping systems, particularly those dealing with parallel flow configurations.

hydronicengr
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Let's say I have a simple parallel flow problem as shown in the attachment. The flow is pressurized and the downstream of the return goes back to a piping system that is negligible. It does not vent to atmosphere.

I've tried reading up on the subject, but I got stuck at a certain point. At point A, I know that the flow going in must equal the flow going out to the two pipes. Therefore, it will look like Q = Q1+Q2. Expanding Q1 and Q2 gives me V*A for each respective pipe.

I also know that the head loss of Pipe 1 must equal the head loss of Pipe 2. Expanding those equations, I find that I am faced with an unknown, which is the friction factor for each pipe. The friction factor can be explicitly calculated using the Swamee and Jain formula, but is dependent on the Reynolds Number, which is dependent on the flow velocity, which is ultimately dependent on the flow rate of each of the pipes. After getting the friction factor, everything else is easy. Simply plug the velocities from the head loss equations back into the Q formula shown above and solve for the unknown.

I know one can attain the correct friction factor value by many iterations, but is there a way without doing iterations by hand or by Excel and not fancy software?

Also, how would I find the total pressure loss of the system?

Thanks!
 

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I'd say assume no frictional losses, then solve in terms of bend losses etc. You can then obtain V1 in terms of V2,eg. V1= sqrt(k2/k1)V2 (Where k is the sum of the loss coefficients ,the Ks will vary for each pipe.). Then plug that into Q=A1V1 + A2V2 to get the value of V2, and subsequently Q2 and Q1. The pressure drop in each pipe is the same, so your pressure drop per unit weight (in metres) = k1(V1^2)/2g or k2(v2^2)/2g.
Hope this helps
 

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