Partial Fractoin Integration Check

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Homework Help Overview

The discussion revolves around a partial fraction integration problem, where the original poster seeks validation of their solution and working steps. Participants are reviewing the integration process and the correctness of the final answer.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are examining the arithmetic involved in the integration and substitution steps. There are specific mentions of errors in integration and substitution, particularly concerning the handling of the squared denominator and the constant multipliers in the logarithmic terms.

Discussion Status

Several participants have pointed out mistakes in the original poster's calculations, particularly in the integration and substitution processes. There is an ongoing effort to clarify and correct these errors, with some guidance provided on specific terms that need adjustment. The discussion is active, with participants collaboratively identifying issues without reaching a final consensus.

Contextual Notes

The original poster has provided their working steps, but there are indications of mistakes that need addressing. The discussion includes corrections to specific terms and constants, highlighting the importance of accuracy in integration processes.

Procrastinate
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Partial Fraction Integration Check

Hello, I was just wondering whether my answer for my partial fraction integration question was right. Attached are three pages of my working but the answer is at the bottom of the third page (027) and the question is at the top of the first page (025).

Thanks.
 

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You have a mistake, give me a second to pinpoint where it is.
Oh and by the way, you integrated the fraction at the end with the squared denominator wrong.

[tex]\int \frac{1}{x^2}dx=\frac{-1}{x}[/tex]
 
Ok your arithmetic was wrong when you substituted x=-1/3.
 
Mentallic said:
Ok your arithmetic was wrong when you substituted x=-1/3.

Ok. I fixed that up (as well as my other small integration error.)

My final answer is now:

[tex]\frac{22}{25}\ln|x+2|+-\frac{4}{5(x+2)}+-\frac{2}{75}\ln|3x+1| + C[/tex].

Is this correct?
 
The ln(3x+1) term is incorrect. I get -16/75 as the constant multiplier.
 
Oh yes, that is right. I just accidentally copied it down wrong. Thanks for your help.
 
Mentallic said:
The ln(3x+1) term is incorrect. I get -16/75 as the constant multiplier.

[tex]\frac{22}{25}\ln|x+2|+-\frac{4}{5(x+2)}+-\frac{16}{75}\ln|3x+1| + C[/tex]
 
No problem :smile:
 

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