Peak voltage output of a generator

AI Thread Summary
The discussion focuses on calculating the peak and RMS voltage output of a generator with a 400-loop circular armature coil rotating in a magnetic field. The initial calculation for peak voltage output yielded an excessively high value of 2,960,881V, prompting the author to suspect an error. A critical mistake was identified in the diameter conversion from centimeters to meters, which significantly affected the result. The RMS voltage output is dependent on the corrected peak voltage, with a formula provided for calculation. The confusion around the sine function's value relates to the nature of the generator, suggesting it operates like a DC generator.
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Homework Statement


A 400 loop circular armature coil with a diameter of 5cm rotates at 60rev/s in a uniform magnetic field of strength 1T.

a) What is the peak voltage output of the generator?
b) What is the RMS voltage output of the generator?

The Attempt at a Solution



a) My answer seems a tad large, I think I'm doing something wrong but can't quite pick it...
ε=NBAωsin(ωt)
ε=400*1*(pi*2.5²)*(60*2pi)*1
ε=2960881V

b) RMS=ε*[1/√(2)]
(Leaving it for now as it depends on the answer from part a)
 
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Convert 5cm to 0.05m. Reduces answer by a factor of 10000.
 
apelling said:
Convert 5cm to 0.05m. Reduces answer by a factor of 10000.

Silly me...
 
why is sin(wt) = 1?

is it because its a dc generator?
 

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