Pendulum and Simple Harmonic Motion Problems

[think4432]

1. Determine the value of the acceleration due to gravity on planet X if a pendulum having a length of 30.0 cm has a frequency of .70 hz on that planet?

2. Find the period of motion for a 200 gram mass vibrating on a spring having a spring constant of 4.0 n/m?

3. When a mass of 35.0 grams is attached to a certain spring, it makes 20 complete vibrations in 4.80 seconds. What is the spring constant for this spring?


equations: SHM: T=2pi sqr(m/k)


1. i have no idea...really
2. t=2pi sqr(200g/4 n/m) = 44.4288
3. k=4pi^2m/t^2
k=4pi^2(35g)/(4.1s)^2 [t=4.1s]
k=82.19 N/M


I don't understand the spring constant equation.

Please help?

 

[rock.freak667]

1) You know that the period of a pendulum is
T = 2\pi \sqrt{\frac{l}{g}}

and that f= \frac{1}{T}

2)Should be correct since you are using the correct formula

3) The periodic time, T is the time taken for one vibration.

20 vibrations occur in 4.8 s
1 vibration will occur in how much time?

Now use the equation T=2pi sqr(m/k) and rearrange it to get k

 

[think4432]

Ohh! Ok! I understand number 2, and 3.

But number 1 is still a little confusing.

So, T=2pi sqrt(L/a)
Frequency, f=1/T
f=(1/2pi)sqrt(a/L)

solve for a?

a=(1/4pi^2)L/T^2
(1/4pi^2)(30cm)/1.42^2

a=36.70 m/s^2 ?



and one more problem:
A 70.0 gram mass is hung from a vertical spring causing it to stretch 20.0 cm. Find the period of motion for this system when the 70.0 gram mass is replaced by a 90.0 gram mass and set into simple harmonic motion.

how would i set that up?

thanks for the help on the other 2 problems! :]

 

[rock.freak667]

Ohh! Ok! I understand number 2, and 3.

But number 1 is still a little confusing.

So, T=2pi sqrt(L/a)
Frequency, f=1/T
f=(1/2pi)sqrt(a/L)

solve for a?

a=(1/4pi^2)L/T^2
(1/4pi^2)(30cm)/1.42^2

a=36.70 m/s^2 ?

Yes solve for a. But recheck your rearranging of terms.

f = 1/2pi sqrt(a/l)
f²= (1/4pi²)(a/l)

and one more problem:
A 70.0 gram mass is hung from a vertical spring causing it to stretch 20.0 cm. Find the period of motion for this system when the 70.0 gram mass is replaced by a 90.0 gram mass and set into simple harmonic motion.

how would i set that up?

When you placed the 70g mass (the weight causes it to stretch) on the spring it stretched by 20 cm, as it said right?
Remember Hooke's law? You can now find the spring constant,k.

When you have k, to find the period when the mass is 90grams just use the formula you stated above:

T= 2\pi \sqrt{\frac{m}{k}}

 

[think4432]

thank you so much!

great help!

now i might pass the test tommorow!

thanks again!

 

[skiing4free]

2. t=2pi sqr(200g/4 n/m) = 44.4288

! 200g=.2kg! ALWAYS CONVERT, you CANNOT multiply grams by meters it WONT WORK!