Pendulum Problem with unknown angle

  • Thread starter Thread starter jg727
  • Start date Start date
  • Tags Tags
    Angle Pendulum
AI Thread Summary
To find the speed of a pendulum ball at an angle θ, one can use an energy approach. The initial kinetic energy (Ek) is straightforward to calculate, while potential energy (PE) at angle θ can be determined using the formula PE = mgh. The height (h) can be derived from the string length (L) and the angle θ. By equating the initial energy to the energy at angle θ, the speed (v) can be expressed as a function of mass (m), gravitational acceleration (g), string length (L), and angle (θ). Understanding how to calculate potential energy is crucial for solving this problem.
jg727
Messages
4
Reaction score
0
A pendulum (with string length "L") and aball of mass "m" is pulled back to a horizontal position and then released. Assuming that θ is the angle between the string and the vertical, find the speed of the ball (v) at an angle of θ as a function of m,g,L, and/or θ.


I just can't get my mind around this problem...
 
Physics news on Phys.org
Welcome to PF, jg!
I could be horrendous using motion formulas.
Have you considered an energy approach? The initial Ek is easy. Can you find the height when at angle θ and thus the potential energy? From that you can get the Ek at θ and then the speed.
 
Thank You!
Ok, so I guess I am actually having problems with finding the potential energy. I'm completely blanking.
 
PE = mgh
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Replies
15
Views
1K
Replies
9
Views
2K
Replies
20
Views
2K
Replies
6
Views
5K
Replies
3
Views
2K
Replies
1
Views
811
Replies
2
Views
6K
Replies
5
Views
2K
Back
Top