Physics Homework - Coefficent of friction.

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Homework Help Overview

The discussion revolves around calculating the coefficient of friction in two scenarios involving cars: one where a car slides to a stop and another where a car accelerates under an applied force. The subject area is primarily focused on friction and energy concepts in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between kinetic energy loss and the work done by frictional forces. Questions arise regarding the calculation of the frictional force and its relationship to the applied force.

Discussion Status

Some participants have offered insights into the equations relating kinetic energy and frictional forces, while others are questioning how to determine the frictional force in the context of the problems presented. Multiple interpretations of the relationships involved are being explored.

Contextual Notes

There is a noted confusion regarding multi-step problems and the application of concepts related to friction and energy. Participants are seeking clarification on definitions and relationships without providing complete solutions.

Huskies101
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I understand what to do for single step problems, but I get lost when it comes to multi-stepped. Help, please!

1. A 2000 kg car traveling at 20 m/s slides to a stop over a distance of 200 m on a snowy level road. What is this coefficient of friction between car's tires and the road?

2. A 3000 kg car accelerates along a level road at a rate of 1.5 m/s when 5500 N of force is applied. What is its coefficient of friction?

Honestly, I am completely lost, and I do need help. So please, can you help me?
 
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Kinetic energy lost by the car is equal to the work done by the frictional force.
Coefficient of friction = ...?
 
rl.bhat said:
Kinetic energy lost by the car is equal to the work done by the frictional force.
Coefficient of friction = ...?

I know coefficient of friction = us= FnFf. But how do I find Ff? (Frictional force.) Is it the same as the force applied?
 
Frictional force X displacement = Loss of KE
And us = Ff/Fn
 
Kinetic Friction Force=the product of the coefficient of the kinetic friction AND the normal force
"Ffk=μkFn"
 

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