Physics lab, calculating/combining errors

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The discussion focuses on calculating combined errors in physics lab experiments, specifically for time, distance, and acceleration. For T = 0.433 ± 0.004 s, the task is to calculate T^2 and ΔT^2 using error propagation principles. When calculating distance d = vt with v = 55 mi/hr ± 5% and t = 5.00 ± 0.03 hrs, it is essential to convert the percentage error into a numerical value and apply the formula for Δd. For acceleration a = 2d/t^2, given d = 82.0 ± 0.2 cm and t = 4.23 ± 0.05 s, the appropriate error propagation formulas must be utilized to find Δa. Understanding these calculations and error propagation techniques is crucial for accurate results in physics experiments.
cjweidle
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I just started the semester off in physics lab and I am so rusty. I did three perfectly okay by myself but these last three I can't seem to figure out. Any help on the direction to take with these is appreciated!

c) T = 0.433 ± 0.004 s. Calculate T^2 andΔT^2.

d) Given d = vt, v = 55 mi/hr ± 5% and t = 5.00± 0.03 hrs, calculate d and Δd.
Like here do I put in d= (55 ± 5%)(5.00 ± 0.03)
I know I have to get the percent into an actually number, I can do that. but I don't know if this is the way to go about it and then I really don't know how to get Δd.

e) Given a = 2d/ t2 , d = 82.0 ± 0.2 cm and t = 4.23 ± 0.05 s, calculate a and Δa.
 
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Hint:

C) If X = a ± b then ΔX ^ n = X ^ n * ( n * ( ΔX / X ) ) = a ^ n ( n * (b / a ) )

D) Δd = Δ(vt) = vt ( ΔV / V + Δt / t )

E) Δ(2d/t^2) = 2d/t^2 ( Δd/d + Δt^2/t^2)
 
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