Potential of concentric cylindrical insulator & conducting shell. Stuck on 2nd question

AI Thread Summary
The discussion focuses on calculating the electric field and potential difference between a charged insulating cylinder and a concentric conducting shell. The electric field at a specific point, R, is determined to be -7897.28 N/C. For the potential difference V(c) - V(a), the approach involves using the electric field derived from a Gaussian surface and integrating it from the cylinder to the shell. The user suggests a formula involving charge and distance to find the potential difference. The conversation emphasizes the need for clarity in calculations and further engagement for problem-solving.
Richard Ros
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An infinitely long solid insulating cylinder of radius a = 5.2 cm is positioned with its symmetry axis along the z-axis as shown. The cylinder is uniformly charged with a charge density ρ = 23 μC/m3. Concentric with the cylinder is a cylindrical conducting shell of inner radius b = 14.2 cm, and outer radius c = 16.2 cm. The conducting shell has a linear charge density λ = -0.45μC/m.

1. What is Ey(R), the y-component of the electric field at point R, located a distance d = 58 cm from the origin along the y-axis as shown?
-7897.28N/C

2. What's V(c)-v(a), the potential difference between the outer surface of the conductor and the outer surface of the insulator.
KQ
My Attempt : Vc - Va = kq/c - kq/a
vc - va = qk * (1/c - 1/a)
 
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Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 
First find the E field using a gaussian surface, then integrate E from the cylinder to the shell.
 
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