Power loss in sinusoidal electric fields

JerryG
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Homework Statement


In my electromagnetics book, in the section that talks about loss tangents, the equation for average power dissipation per unit volume is P=(1/2)*J*E (W/m^3). What does the coefficient of 1/2 come from? Earlier in the book, it gave the differential power dissipation dP= J*E (W/m^3)

Homework Equations


J = current density.
E= electric field.
 
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Is it possible that previously E was a constant value, and now E is the peak value of a sinusoid?
 
gneill said:
Is it possible that previously E was a constant value, and now E is the peak value of a sinusoid?

That's it. It's the Erms ^ 2 that gives the 1/2.
 
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