Problem relating to the Heisenberg's Principle

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SUMMARY

The discussion centers on calculating the velocity of an electron confined in a box of size 1*10^-10m using Heisenberg's Uncertainty Principle. The relevant equations include Heisenberg's equation, specifically xp=h/2π and xmv=h/2π. The calculated velocity is 7.29*10^6 m/s, but confusion arises regarding the correct application of the principle, particularly the distinction between the equations involving 2π and 4π. The participant questions the validity of their answer compared to the textbook solution.

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Homework Statement


An electron is placed in a box about the size of an atom that is about 1*10^-10m. What is the velocity of the electron?


Homework Equations


Heisenberg's equation
xp=h/2pi
xmv=h/2pi
v=h/2pi*x*m
where x=1*10^-10m
m=9.1*10^-31kg
h=planck's cosntant


The Attempt at a Solution



Answer is 7.29*10^6
 
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Was this REALLY the question? The uncertainty principle states that:

\Delta x \Delta p \geq \frac {h} { 4 \pi}

NOT

x p = \frac {h} { 4 \pi}


(I don't know how to do the reduced Planck's constant in Latex)
 
So it's 4pi not 2pi? Actually the answer I'm getting is different from that which is given at the end of my physics book.
And while solving the problem, doesn't it become \Deltax\Deltap=h/4pi?
 

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