Proving a system is LTI based on input and output

AI Thread Summary
The discussion revolves around determining if a given system can be classified as Linear Time-Invariant (LTI) based on its input-output relationship. The input is defined as x(t) = -5cos(2t), and the output is y(t) = exp(-2tj). The user attempts to find a transfer function H(s) to relate the input and output but struggles due to the lack of Laplace transform knowledge, which is not covered until a later chapter. The consensus indicates that if the output is a scaled version of the input, it could potentially be considered LTI, with the provided answer suggesting that H(s=2j) equals zero. The discussion emphasizes the importance of understanding the relationship between the input and output forms to classify the system correctly.
robijnix
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edit: you aren't proving it's LTI, you proving it COULD be lti

Homework Statement


the question:
could the following system be LTI?
x(t)=-5cos(2t) --> y(t)=exp(-2tj)

Homework Equations


the chapter is about eigenfunctions of LTI systems, which are of the form exp(st).

The Attempt at a Solution


So my guess for what i had to do, was find a transfer function H(s), so that H(s)*x(s)=y(s).
so i wrote x(t) as follows:
x(t)=-5/2(exp(2*t*j)+exp(-2*t*j)
so
x(2)=-5/2(exp(st)+exp(-st)) with s=2j.

so than i thought, H(s)=y(s)/x(s), but y and x are still functions of t, so i don't know what to do now...

and btw laplace isn't explained until the next chapter so I'm not supposed to use that.

the given answer is 'yes (H(s=2j)=0)'.
so i think i do indeed need to do something with the transfer function.
 
Physics news on Phys.org
If the output is of the same form as the input but scaled by a constant is that an LTI system? Is the output the same form as the input? (coefficient of sin could be 0)
 
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