Gymnast's Floor Routine: Angular Velocity & Time

AI Thread Summary
A gymnast's floor routine involves a tumbling run where she increases her angular velocity from 3.00 to 4.65 revolutions per second while completing half a revolution. To calculate the time taken for this maneuver, one must apply kinematic equations relevant to rotational motion. The term "one-half of a revolution" corresponds to an angle of 180 degrees or π radians. Understanding this angle is crucial for determining the time required for the gymnast's spin. The discussion emphasizes the importance of kinematic principles in solving problems related to angular motion.
ussjt
Messages
41
Reaction score
0
A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3.00 to 4.65 rev/s while rotating through one-half of a revolution. How much time does this maneuver take?

ok I understand that I am going to be using one of the equations of kinematics for rotational and linear motion. I just don't understand what I am suspose to use the "one-half of a revolution" for.
 
Physics news on Phys.org
What angle is one half of a revolution?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top