Rank Resistors by Energy Dissipation: 5Ω > 10Ω > 20Ω > 90Ω

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The discussion focuses on ranking resistors by energy dissipation, emphasizing the relationship between resistance and power dissipation in both series and parallel configurations. The calculations reveal that the 5Ω resistor dissipates more energy than the 10Ω and 20Ω resistors when connected in parallel, while the 90Ω resistors dissipate power equally. When considering equivalent resistances, the 10Ω, 5Ω, and 20Ω combination yields approximately 2.86 ohms, while the two 90Ω resistors result in 45 ohms. The final ranking of energy dissipation is established as 90Ω = 90Ω > 20Ω > 10Ω > 5Ω. The analysis confirms that parallel circuits generally absorb more power than series configurations.
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Homework Statement


Rank the resistors according to to the rate at which energy is dissipated in them.

Mazur1e.ch31.p88.jpg


Homework Equations


P = I2R
P = V2/R
Iin=Iout at a node

The Attempt at a Solution


First I looked considered the 20 Ω (top) and the 10 Ω(bottom). The current in them would be the same, so then applying the equations you get that the energy dissipated in the 20 Ω(top) > 10 Ω(bot).
Next I looked at the 10, 5, and 20 Ω resistors in parallel. Resistors in parallel have the same voltage. Therefore, I concluded that the energy dissipated in the 5 Ω > 10 Ω > 20 Ω.
Again I was thinking that the voltage would be same in the two 90 Ω resistors, so I have their energy dissipated equal, 90Ω(left) = 90Ω(right).

I think I did that part right. However, I do not know how to go about comparing these three sets. I feel that it would be 5Ω > 10Ω > 20Ω > 90Ω = 90Ω > 20Ω(top) > 10Ω(bottom) since parallel circuits take more energy than a series configuration. Does this look correct? Thanks in advance for any help!
 
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find the equivalent of each parallel combination to reduce the circuit to a single mesh
the resultant of (10,5,20) will be less than 5 so it will absorb the least amount of power
(90,90)--> 45, the most amount.
______________________________
"parallel circuits take more energy than series" you said, this is right when you are talking about the same resistors
if connected (10,5,20) in series with a 5V voltage source they well absorb less power than if they are connected in parallel
 
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Passionate Eng said:
find the equivalent of each parallel combination to reduce the circuit to a single mesh
the resultant of (10,5,20) will be less than 5 so it will absorb the least amount of power
(90,90)--> 45, the most amount.

The equivalent resistance from the 10,5,20 is approximately 2.86 ohms, and for 90,90 is, as you said, 45 ohms. So you're saying that the order would then be [90=90]>20(top)>10(bottom)>[5>10>20]?
 
exactly
 
mattbeatlefreak said:
The equivalent resistance from the 10,5,20 is approximately 2.86 ohms, and for 90,90 is, as you said, 45 ohms. So you're saying that the order would then be [90=90]>20(top)>10(bottom)>[5>10>20]?
mattbeatlefreak said:
The equivalent resistance from the 10,5,20 is approximately 2.86 ohms, and for 90,90 is, as you said, 45 ohms. So you're saying that the order would then be [90=90]>20(top)>10(bottom)>[5>10>20]?
That is the correct order. The analysis you have looks a bit shy of actually showing that order, unless I missed something.

For instance, if there was a 30 Ω resistor replacing the 20 Ω resistor the order would be different.

The pair of 90 Ω resistors in parallel would dissipate more power than a 30 Ω resistor which is in series with the pair. However, combined they would dissipate less than twice the power, so that each dissipates lees than the 30 Ω resistor.
 
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