Real life examples of simultaneity

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Real-life examples of simultaneity highlight how observers can perceive events differently based on their relative motion and distance. The discussion emphasizes that simultaneity is not typically observed in everyday life due to the small relative speeds of people on Earth, making the effects negligible. A key example involves two observers, A and B, separated by a significant distance, where A sees a light turn on before B due to the finite speed of light. However, if both observers are at rest relative to each other, they would agree on the timing of events. The conversation ultimately clarifies that relativity of simultaneity becomes significant only at speeds approaching that of light, making it a complex but fascinating aspect of physics.
  • #31
Consider lightning strikes at points A and B and for an observer at midpoint M on the embankment (reference frame K) the events occurred simultaneous because the light beams reach him or her at the same time.

Suppose when lightning strikes at A and B for an observer who when the events occur at A and B is at midpoint M but moving at 1/2 c (speed of light) toward point B, which is moving towards M' at c. Figure c = 300,000km/s. At what point on x can we identify M' to meet with B'? So B' = c and M' = 1/2c or c/2. They move toward each other in a straight line in vacuum at these velocities. What point do they meet. Convert to meters when appropriate to do so. I will be very suprised if anyone's wisdom and analysis can find the answer number to this riddle. The meaning of this is speaks to the relativity of simultaneity.
 
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  • #32
vela said:
When A, B, and M see the light from the lighting bolts striking is different than when the lightning bolts strike. Because they are all at rest relative to each other, they will all agree that the bolts hit at the same time after accounting for light travel time. For example, A does not see the light from B until t=1 s, but because A knows B is one light-second away, A concludes that the bolt hit B at t=0 s.

If there were another observer, C, moving relative to them, even after accounting for the time it took the light to travel, C would say that the bolts hit at different times.

I thought the guy in the middle would see them at the same time.
 
  • #33
goodabouthood said:
But what about the person situated in the middle of AB?

Wouldn't he see the lightning bolts at the same time?
Yes, he would see the bolts hit A and B at the same time. The light from both would reach him when t=0.5 s. Knowing he was right in the middle of A and B, he would then conclude that the bolts hit A and B at t=0 s.
 
  • #34
vela said:
Yes, he would see the bolts hit A and B at the same time. The light from both would reach him when t=0.5 s. Knowing he was right in the middle of A and B, he would then conclude that the bolts hit A and B at t=0 s.

Now wouldn't that be relative simultaneity because person M sees both lighting bolts at the same time but person A and person B see them at different times?

Person A and B will not agree with the person M when the bolts striked.

At least that is what I thought simultaneity was.
 
  • #35
CLSabey said:
Consider lightning strikes at points A and B and for an observer at midpoint M on the embankment (reference frame K) the events occurred simultaneous because the light beams reach him or her at the same time.

Suppose when lightning strikes at A and B for an observer who when the events occur at A and B is at midpoint M but moving at 1/2 c (speed of light) toward point B, which is moving towards M' at c. Figure c = 300,000km/s. At what point on x can we identify M' to meet with B'? So B' = c and M' = 1/2c or c/2. They move toward each other in a straight line in vacuum at these velocities. What point do they meet. Convert to meters when appropriate to do so. I will be very suprised if anyone's wisdom and analysis can find the answer number to this riddle. The meaning of this is speaks to the relativity of simultaneity.


In the stationary frame they meet at 1/3 the distance between M and B.

If you want A' too, that meets at 2 times the distance between M and A.
 
  • #36
vela said:
Yes, he would see the bolts hit A and B at the same time. The light from both would reach him when t=0.5 s. Knowing he was right in the middle of A and B, he would then conclude that the bolts hit A and B at t=0 s.

You are presuming the line AB to be 300,000km then. Time is only significant when we know the reference frame for the events which we speak of. Here we could use any value for time so long as the beams of light resulting from the bolts reached M at same time, whatever that time may be from t=0 which coincides to origin of events A and B (lightning bolts). Whatever the t'= x then you can determine distance of lines AM and BM by dividng time in half and multiplying by distance in speed of light (use seconds for t).

Let's say it takes one second for light beams from A and B to reach you. The line AB is 600,000 km/s.
 
  • #37
No, they all agree that the bolts hit at t=0 s, even though they didn't know about the strikes until some time later when the light was able to propagate from the event to the observer.

The relativity of simultaneity happens between observers moving relative to each other. Since A, B, and M are all at rest to one another, they all agree that the bolts hit at the same time, even though they didn't see the bolts hit until later. Again, when an observer sees the event and when the event actually happened are two different things.

Say you had an observer C going from A to B who passes M at t=0 s, the time the lightning bolts strike. From A, B, and M's point of view, the light from B will reach C before the light from A does because C is moving toward the light coming from B and away from the light coming from A. C also agrees that the light from B reached him before the light from A, but he also knows that A and B were at the same distance from him. If the light from B reached him first, it must be because the lightning hit B before the lightning hit A. To C, the events weren't simultaneous.
 
  • #38
PatrickPowers said:
In the stationary frame they meet at 1/3 the distance between M and B.

If you want A' too, that meets at 2 times the distance between M and A.

I want when M' and B' meet. What specifically is the number of the point they meet. No ratios or relations or descriptives just the number.
 
  • #39
CLSabey said:
You are presuming the line AB to be 300,000km then.
Yes, because that's the set-up goodabouthood made up. Something happens at A and B sees it one second later. M being in the middle would be a half light-second away from A and B.
 
  • #40
Yes you are right
 
  • #41
vela said:
No, they all agree that the bolts hit at t=0 s, even though they didn't know about the strikes until some time later when the light was able to propagate from the event to the observer.

The relativity of simultaneity happens between observers moving relative to each other. Since A, B, and M are all at rest to one another, they all agree that the bolts hit at the same time, even though they didn't see the bolts hit until later. Again, when an observer sees the event and when the event actually happened are two different things.

Say you had an observer C going from A to B who passes M at t=0 s, the time the lightning bolts strike. From A, B, and M's point of view, the light from B will reach C before the light from A does because C is moving toward the light coming from B and away from the light coming from A. C also agrees that the light from B reached him before the light from A, but he also knows that A and B were at the same distance from him. If the light from B reached him first, it must be because the lightning hit B before the lightning hit A. To C, the events weren't simultaneous.

This actually helps. The guy at C actually experiences the event before the others. The event of seeing the lightning B actually happens for him first.
 
  • #42
goodabouthood said:
Now wouldn't that be relative simultaneity because person M sees both lighting bolts at the same time but person A and person B see them at different times?

Person A and B will not agree with the person M when the bolts striked.

At least that is what I thought simultaneity was.

Well it depends on context.

With that perspective their experience is what is used to define "right Now". And your right they didn't experience each lighting strike at the same time, and in that sense wasn't simultaneous.

After the group measures how much time (this is key, they measure time the same) elapsed between events, they measure the distance between themselves and using their time and distance measurements, A, B & M calculate that the lighting strikes flashed at the same time.
 
  • #43


That is the train example. It's most likely a better example than the one I tried to give.

So events actually happen for some FoR than they do for other FoR.
 
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  • #44
So let's say that the guy on the platform has a clock and the girl on the train also has a clock that are synchronized.

Special relativity tells us that even if they are reading synchronized clocks the events that happen would be different for them at particular times. They couldn't agree.

I understand this more now. Thanks.
 
  • #45
good. I think in your example before, you were confusing two different events: the lightning bolt hitting the ground, and the light from it going into someone's eye. These two events are different because light travels from one place to another. They are not different due to relativity of simultaneity.
 
  • #46
goodabouthood said:
So let's say that the guy on the platform has a clock and the girl on the train also has a clock that are synchronized.

Special relativity tells us that even if they are reading synchronized clocks the events that happen would be different for them at particular times. They couldn't agree.

I understand this more now. Thanks.

If their clocks are synchronized (adjusted for differences in measuring time) they would agree on the time of events, like with the GPS.

Another way to say it is SR/GR redifined the concept of simultaneous with the postulate c is invariant.
 
  • #47
nitsuj said:
goodabouthood said:
So let's say that the guy on the platform has a clock and the girl on the train also has a clock that are synchronized.

Special relativity tells us that even if they are reading synchronized clocks the events that happen would be different for them at particular times. They couldn't agree.

I understand this more now. Thanks.
If their clocks are synchronized (adjusted for differences in measuring time) they would agree on the time of events, like with the GPS.

Another way to say it is SR/GR redifined the concept of simultaneous with the postulate c is invariant.
In the example of the train and the platform, it is not possible to adjust the clocks so that they remain synchronized. Identical, unadjusted clocks will run at different rates in a symmetrical, reciprocal way, making it impossible to tweak them so that they can run at the same rate. The platform observer sees the train clocks ticking slower than his own and the train observer sees the platform clocks ticking slower than her own.

This is the point that has been repeated many times on this thread: clocks moving inertially (in a constant direction at a constant speed) with respect to each other run at different rates and cannot be synchronized, and Frames of Reference moving with respect to each other will have different definitions of the synchronization of the clocks at rest in their respective frames.

It's a different story with the time dilation caused by gravity where clocks at different altitudes and/or in orbit run at different rates, but there the relationship is not symmetrical and reciprocal which allows them to be tweaked so that they can display the same time and remain "synchronized". So, for example, the atomic clocks at Greenwich, England, run at a different rate from identical clocks at Boulder, Colorado, but they both agree on the difference because its not symmetrical and reciprocal, so they can both be used as standards for the second here on Earth with appropriate tweaking.

And goodabouthood, you're still confused on the meaning of "event" as used in relativity. Please study this recent https://www.physicsforums.com/showthread.php?t=543416" and see if it helps you.
 
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  • #48
Here is a space-time diagram to help you visualize what special relativity is representing in the train-lightening example. Try to imagine a 4-dimensional universe with 4-dimensional objects (the train passenger car, the observer on the platform and the observer in the train car--these are all 4-D objects). These objects extend into the 4th dimension in the sketch below. A 4-D object corresponding to motion along X1 is slanted in the 4th dimension (the 3-D representation of the object moves along its 4th dimension at the speed of light). Google "space-time diagram" and "Block Universe" to get insight into these concepts. It's likely that you will not really get a good grasp of special relativity until you can comprehend a space-time diagram.
Einstein_Train3.jpg
 
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  • #49
Wow--if I thought I had to comprehend space-time diagrams before I could really get a good grasp of special relativity, I'd have given up a long time ago, especially when you promote this 4-D "Block Universe" version which is not mainstream SR but rather a philosophical speculation. Why don't you stick with the legitimate 1-D version as described in the wikipedia "Minkowski diagram" article? And since they are inherently 1-D, how can they illustrate the difference in length contraction along a second dimension?
 
  • #50
1. My idea of an event is pretty much an instant in time where something happens.

2. The idea in my head about all of this is that the observer on the platform and the observer on the train experience one of the events together. That would be the lighting bolt that hit B.

The lightning bolt hitting A would happen at the same time as B for the observer on the platform so he would think that these events were simultaneous. The observer on the train is moving towards B so the lightning bolt from A has to catch up to him so he would not think these events were simultaneous.

Is this correct?
 
  • #51
ghwellsjr said:
Wow--if I thought I had to comprehend space-time diagrams before I could really get a good grasp of special relativity, I'd have given up a long time ago, especially when you promote this 4-D "Block Universe" version which is not mainstream SR but rather a philosophical speculation. Why don't you stick with the legitimate 1-D version as described in the wikipedia "Minkowski diagram" article? And since they are inherently 1-D, how can they illustrate the difference in length contraction along a second dimension?


I'll take up the sword in defense of the Block Universe concept. I don't believe that the world is actually this way, but it is a very useful idea nonetheless. In mathematics it is quite often the case that if you can get the element of time out of the problem then everything gets easier. So it helps a lot to be able to think this way.
 
  • #52
goodabouthood said:
1. My idea of an event is pretty much an instant in time where something happens.

2. The idea in my head about all of this is that the observer on the platform and the observer on the train experience one of the events together. That would be the lighting bolt that hit B.

The lightning bolt hitting A would happen at the same time as B for the observer on the platform so he would think that these events were simultaneous. The observer on the train is moving towards B so the lightning bolt from A has to catch up to him so he would not think these events were simultaneous.

Is this correct?
No, did you study the thread I asked you to?
 
  • #53
Well I see this:

"The “time” of an event is that which is given simultaneously with the event by a stationary clock located at the place of the event, this clock being synchronous, and indeed synchronous for all time determinations, with a specified stationary clock."

So if you were on the platform and saw both lightning bolts hit and your clock read 8:00pm that would be the time of the two events for said person. The two events would be simultaneous for this person on platform.

Please explain if I my interpretation of the train example is wrong.
 
  • #54
What's wrong with your interpretation is that even though your statement in your second paragraph is correct, you then went on to talk about the observer seeing the two lightning bolts and looking at his clock and seeing a time of 8:00pm on it. The observer's clock is of no consequence. He doesn't even need a clock to see that the images of the two lightning bolts arrive at his location simultaneously. But what is important is the times on the two separate clocks located where the lightning bolts occurred when they occurred. These clocks will have an earlier time on them and they define the two events, along with their locations. The observer has no knowledge of the lightning strikes until some time later.

You have to imagine a multitude of synchronized clocks spread out everywhere in the space defined by a Frame of Reference. At each location is the spatial coordinates of each clock. The combination of the time on each clock, plus its location, is defined as an event. It has nothing to do with any observers or when they see anything that might be happening.

So, in a Frame of Reference where the ground is stationary, the event of the lightning strike at the front of the train and the event of the second lightning strike at the rear of the train are simultaneous because the two events defined by the two clocks at those two locations we are told have the same time reading on them. We are told that indirectly by virtue of the fact that the light from those two events arrives simultaneously at a point midway between them. That's the way the scenario is set up.

So given that the scenario is set up so that the events of the lightning strikes occur at the same time according to the definition of time in the ground reference frame, if we want to see what the times of those same two events are in a different Frame of Reference moving with respect to the first one, we need to use the Lorentz Transform to take the x, y, z and t coordinates of each event of interest and transform them into the second FoR.

So for simplicity's sake, let's say that the speed of light is 1 foot per nanosecond and let's say the train is traveling at 0.6c and it is 1000 feet long. We could establish some coordinates and use the Lorentz Transform to see what the time coordinates of those two events are and subtract them to see what the difference between them is but since BruceW gave you a concise formula to calculate this difference in post #3, let's go ahead and use that. In his formula, β=0.6 and Δx equals 1000 feet or in compatible units, it is 1000 light nanoseconds or 1 light microsecond. Here's BruceW's formula:
\frac{\beta}{\sqrt{1- \beta^2}} \Delta x
You can easily see that this evaluates to 0.75 microseconds.

Note that this evaluation has nothing to do with the observers in the scenario.

I think what is confusing in the video is the introduction of the observers and the "interpretations" of what they are seeing as if that is what are the events in question.
 
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  • #55
goodabouthood said:
1. My idea of an event is pretty much an instant in time where something happens.

2. The idea in my head about all of this is that the observer on the platform and the observer on the train experience one of the events together. That would be the lighting bolt that hit B.

The lightning bolt hitting A would happen at the same time as B for the observer on the platform so he would think that these events were simultaneous. The observer on the train is moving towards B so the lightning bolt from A has to catch up to him so he would not think these events were simultaneous.

Is this correct?

I can understand your attention focused on the guy in the middle of the car moving away from the point on the ground that the lightning hit. But the answer to your question is "No." The focus in this example should be on the special relativity effects relating to the relativistic speed of the train.

Did you understand the space-time diagram? You can see that the guy on the train is living in a different 3-dimensional world than the guy on the platform. They are not living in the same simultaneous 3-D spaces. That accounts for the fact that the front and rear flashes are not simultaneous for the guy in the train--those two events are literally not simultaneous in his 3-D world.
 
  • #56
ghwellsjr said:
Wow--if I thought I had to comprehend space-time diagrams before I could really get a good grasp of special relativity, I'd have given up a long time ago, especially when you promote this 4-D "Block Universe" version which is not mainstream SR but rather a philosophical speculation. Why don't you stick with the legitimate 1-D version as described in the wikipedia "Minkowski diagram" article? And since they are inherently 1-D, how can they illustrate the difference in length contraction along a second dimension?

That's not an unreasonalble response, ghwellsjr. Thanks for the comments. But, it has been my experience that the "light" has really suddenly turned on for my students who came to an understanding of the space-time diagrams. Length contraction, time dilation, constant speed of light and all of the "paradoxes" seem so obvious and easily explained with the aid of space-time diagrams. But, it does take a little persistence initially to get a handle on it, so I understand your initial reaction to my suggestion.

My approach was to never introduce the block universe concept until students began to ask about it. It was always interesting to see which students would see the implication of a block universe after much of a semester of working with space-time diagrams.

And could you describe the geometrization of the world without some equivalent to the Block Universe? Are you saying that the universe is not 4-dimensional (perhaps more dimensions if string theory pans out)?

Could you give me the link for the wikipedia article.
 
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  • #57
ghwellsjr said:
In the example of the train and the platform, it is not possible to adjust the clocks so that they remain synchronized. Identical, unadjusted clocks will run at different rates in a symmetrical, reciprocal way, making it impossible to tweak them so that they can run at the same rate. The platform observer sees the train clocks ticking slower than his own and the train observer sees the platform clocks ticking slower than her own.

This is the point that has been repeated many times on this thread: clocks moving inertially (in a constant direction at a constant speed) with respect to each other run at different rates and cannot be synchronized, and Frames of Reference moving with respect to each other will have different definitions of the synchronization of the clocks at rest in their respective frames.

It's a different story with the time dilation caused by gravity where clocks at different altitudes and/or in orbit run at different rates, but there the relationship is not symmetrical and reciprocal which allows them to be tweaked so that they can display the same time and remain "synchronized". So, for example, the atomic clocks at Greenwich, England, run at a different rate from identical clocks at Boulder, Colorado, but they both agree on the difference because its not symmetrical and reciprocal, so they can both be used as standards for the second here on Earth with appropriate tweaking.


And goodabouthood, you're still confused on the meaning of "event" as used in relativity. Please study this recent https://www.physicsforums.com/showthread.php?t=543416" and see if it helps you.

So a moving clock could not have it's measurement of (proper?) time adjusted to match the time of a stationary clock? I need to read about this "Identical, unadjusted clocks will run at different rates in a symmetrical, reciprocal way, making it impossible to tweak them so that they can run at the same rate." I don't understand what it means.

Is it because both observers see the others clock as ticking slower, so adjusting either clock to "correct" for the difference for one observer's clock would exaggerate the difference for the other observers clock?

To say it differently, does the symmetry of SR time dilation reffer to how two observers in relative motion obeserve the others clock as ticking slower?
 
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  • #58
bobc2 said:
I can understand your attention focused on the guy in the middle of the car moving away from the point on the ground that the lightning hit. But the answer to your question is "No." The focus in this example should be on the special relativity effects relating to the relativistic speed of the train.
This thread is about the meaning of simultaneity. The purpose of the train example is to show that in one Frame of Reference (where the ground is at rest), the two lightning bolt events that occur at different locations nevertheless occur at the same time, not because nature demands it, but because the clocks that are located at those two events have been previously synchronized and the problem is stated such that they are simultaneous. That's one point to focus on.

The second point to focus on is that the events defined according to one FoR need to be at different locations, otherwise two events at the same location and the same time are not two events but one event (they have the same four coordinates).

The third point to focus on is that in many other FoR's (not all, just some), those same two events, when transformed into a set of new coordinates will have a totally different set of four coordinates and the time components may be different in which case they are not simultaneous in that FoR.
bobc2 said:
Did you understand the space-time diagram? You can see that the guy on the train is living in a different 3-dimensional world than the guy on the platform. They are not living in the same simultaneous 3-D spaces. That accounts for the fact that the front and rear flashes are not simultaneous for the guy in the train--those two events are literally not simultaneous in his 3-D world.
But the gal on the train and the guy on the platform are both living in the same world. There's only one world. The issue is how we describe the 3 spatial coordinates and the 1 time coordinate that define an event--what numbers do we (and they) use? The gal on the train can use a Frame of Reference where the ground is stationary (of which there are an infinite such FoR's) and in which the two events will be simultaneous and the guy on the platform can use a FoR in which the train is stationary (of which there are an infinite such FoR's) and in which the two events will not be simultaneous. But whichever FoR is used, it includes everyone and every thing. People, other observers and objects don't own their own FoR to the exclusion of the other observers and objects. And it's the FoR that determines if two events are simultaneous not any observers or objects no matter what their states of motion are.

So it's really wrong when discussing the meaning of simultaneity in Special Relativity to link it to particular observers or especially to say that one person lives in a different 3-D world than another one and that's what determines the simultaneity of events, it should only be linked to particular FoR's.
 
  • #59
bobc2 said:
Length contraction, time dilation, constant speed of light and all of the "paradoxes" seem so obvious and easily explained with the aid of space-time diagrams.
How do you show that length contraction only occurs along the direction of motion in a space-time diagram? How do you show the very common example of a light clock with the light bouncing back and forth at right angles to the direction of motion? How would you show that a circular set of mirrors becomes an ellipse when in motion but the light reflecting off of them follows a circular pattern like what is illustrated in robphy's animated glyph on post #9 of this thread?
bobc2 said:
And could you describe the geometrization of the world without some equivalent to the Block Universe? Are you saying that the universe is not 4-dimensional (perhaps more dimensions if string theory pans out)?
In Special Relativity, we focus on a subset of the real world, we ignore gravity and quantum effects and other theories. We model the spatial aspects of the world with three normal, ordinary, everyday, easy-to-understand dimensions and the time aspect of it as in the normal, ordinary, everyday, easy-to-understand way that everyone understands time. But then we define a Frame of Reference that combines the three spatial dimension with time to create the concept of events which are the four coordinates within that particular Frame of Reference. If we use a different Frame of Reference, even another one that is not moving with respect to the first one, we get a different set of four coordinates for each event.
bobc2 said:
Could you give me the link for the wikipedia article.
I did what you said to do:
bobc2 said:
Google "space-time diagram" and "Block Universe"
The first wikipedia hit for the first one was en.wikipedia.org/wiki/Minkowski_diagram as I said here:
ghwellsjr said:
the wikipedia "Minkowski diagram" article
and the first hit for the second one was en.wikipedia.org/wiki/Eternalism_(philosophy_of_time)
 
  • #60
nitsuj said:
So a moving clock could not have it's measurement of (proper?) time adjusted to match the time of a stationary clock? I need to read about this "Identical, unadjusted clocks will run at different rates in a symmetrical, reciprocal way, making it impossible to tweak them so that they can run at the same rate." I don't understand what it means.

Is it because both observers see the others clock as ticking slower, so adjusting either clock to "correct" for the difference for one observer's clock would exaggerate the difference for the other observers clock?

To say it differently, does the symmetry of SR time dilation reffer to how two observers in relative motion obeserve the others clock as ticking slower?
Yes. We're talking here about Relativistic Doppler.

Remember, in our discussion of simultaneity (the subject of this thread), there are not just two clocks moving with respect to each other, there are an infinite number of clocks in two different Frames of Reference. If we give preference to one FoR, it is not possible to tweak all the clocks in the other FoR to match the preferred FoR. If we want to have a preferred FoR, we just use that one and forget about any other FoR and then the issue of simultaneity becomes moot because we treat time as absolute, but that's not what we do in SR.

If you want to talk about just two clocks moving inertially with respect to each other (which has nothing to do with the subject of simultaneity and is not restricted to Special Relativity) then it's a fact of nature that each observer will see the other one's clock as ticking differently than their own in a symmetrical way. If one of them adjusts his clock so that the other one will see it as ticking at the same rate as his own (which can only be done for very restricted types of relative motion), the adjusted clock will then tick at a rate even further removed from the unadjusted clock.

Consider two clocks far removed from each other but have been ticking for a very long time and the image of each of them has reached the other. These two clocks do not have to be moving along the same line, although they could be. If they are moving along the same line toward each other, they will each see the other one as ticking faster than their own. Then when the pass each other, they will immediately see the other one as ticking slower than their own. A similar effect happens when they are not traveling along the same line but the transition is gradual instead of abrupt and they each see the same gradual transistion. The farther away their point of closest approach, the more gradual is the transition. But how in the world can you tweak one of the clocks so that it always appears to be synchronized with the other clock?
 

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