Relativity Question: Solving for E, p, KE and v/c

  • Thread starter kidsmoker
  • Start date
  • Tags
    Relativity
In summary, the poster correctly finds the energies and momenta of the decay products using conservation of energy and momentum, and can use the equation for kinetic energy to find the speed of the decay products with respect to the speed of light.
  • #1
kidsmoker
88
0

Homework Statement



http://img140.imageshack.us/img140/1650/25406466.jpg

Homework Equations



[tex]E^{2}= (pc)^{2}+m_{0}^{2}c^{4}[/tex]

The Attempt at a Solution



To find the energy I said that in the rest frame of the pion, it has energy 139.6Mev, so this has to equal the sum of the energies of the decay products. I then used conservation of momentum to find an equation for the energy of the muon:

[tex]E_{1}=\frac{139.6^2+105.7^2}{2*139.6} Mev = 109.8 Mev [/tex].

And so the energy of the neutrino is

[tex]E_{2}=139.6-109.8 Mev = 29.8 Mev [/tex].

I think these are correct. You can the rest energies from these total energies to get the kinetic energies of each:

[tex]KE_{1} = 109.8-105.7 Mev = 4.1 Mev [/tex]
[tex]KE_{2} = 29.8 Mev [/tex].

The momentum can be calculated by rearranging the equation for [tex]E^{2}[/tex] given above, and I found

[tex]p_{1} = 29.7 Mev/c[/tex]
[tex]p_{2} = 29.8 Mev/c[/tex] .

Hopefully those are all okay. I'm unsure as to how to find the speed with respect to c though. If I rearrange the equation for kinetic energy in order to find v, what is this v with respect to?

Thanks.
 
Last edited by a moderator:
Physics news on Phys.org
  • #2


Dear forum post author,

Your approach to finding the energies and momenta of the decay products is correct. To find the speed of the decay products with respect to the speed of light, you can use the equation for kinetic energy:

KE = (γ - 1)mc^2

where γ is the Lorentz factor given by:

γ = 1/√(1 - v^2/c^2)

You can rearrange this equation to solve for v, which will give you the speed of the decay products with respect to the speed of light. Keep in mind that this speed may be different for each decay product, as they may have different kinetic energies.

I hope this helps! Let me know if you have any further questions.
 
  • #3


Your calculations for energy and momentum seem to be correct. To find the velocity with respect to the speed of light, you can use the equation v = p/E, where p is the momentum and E is the energy. This will give you the velocity in units of c. Alternatively, you could use the equation v = √(1-(m0c^2/E)^2) to find the velocity in terms of the speed of light.
 

1. What is the equation for calculating energy (E) in relativity?

The equation for calculating energy in relativity is E=mc^2, where m is the mass of the object and c is the speed of light.

2. How do you solve for momentum (p) in relativity?

The equation for momentum in relativity is p=mv/√(1-v^2/c^2), where m is the mass of the object, v is the velocity, and c is the speed of light.

3. What is the equation for calculating kinetic energy (KE) in relativity?

The equation for calculating kinetic energy in relativity is KE=mc^2(1/√(1-v^2/c^2)-1), where m is the mass of the object and v is the velocity.

4. How do you calculate velocity (v) in relativity?

To calculate velocity in relativity, you can use the equation v=p/√(m^2c^2+p^2), where p is the momentum and m is the mass of the object.

5. What does the "c" in these equations stand for?

The "c" in these equations stands for the speed of light, which is approximately 3 x 10^8 meters per second in a vacuum.

Similar threads

  • Introductory Physics Homework Help
2
Replies
54
Views
8K
  • Introductory Physics Homework Help
Replies
34
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
898
  • Introductory Physics Homework Help
Replies
6
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
796
  • Introductory Physics Homework Help
Replies
5
Views
1K
Back
Top