Resistance of a water heaters heating element?

AI Thread Summary
To determine the resistance of a water heater's heating element, one must calculate the power required to heat 40 gallons of water from 15°C to 60°C in 15 minutes. The specific heat of water is 4.187 x 10^3 J/(kg·K), meaning it takes 4184 Joules to raise 1 kg of water by 1°C. Given the mass of the water is 151 kg, the total energy needed can be calculated, allowing for the determination of power in watts (J/s). With power known, Ohm's law can be applied to find the resistance using the relationship between power, current, and voltage. Understanding these concepts is essential for solving the problem effectively.
Rijad Hadzic
Messages
321
Reaction score
20

Homework Statement


Household water heaters use a 240 V rather than a 120 V source. What is the resistance of a water heater's heating element if it heats 40 gallons (151 kg) of water from 15 C to 60 C in 15 min

Homework Equations


P = IV
P = I^2R
I = dq/dt

The Attempt at a Solution


Honestly no clue. If anyone can give me some hints I would really appreciate this.

So far I have electrical units, V, and then I have kg, Celcius, and seconds. I'm not sure how the given equations help me relate the units at all.

I need current and power, but those units do not help me at all.

I know I = dq/dt, and I thought 45 C / 900 s looks very similar to current but the units don't make sense to me...
 
Physics news on Phys.org
Do you know how to determine how much heat it takes to raise the temperature of 1 kg of water from 15 C to 60 C?
 
Chestermiller said:
Do you know how to determine how much heat it takes to raise the temperature of 1 kg of water from 15 C to 60 C?

I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
 
Rijad Hadzic said:
I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
Yes. Did you not study heat in freshman physics?
 
Chestermiller said:
Yes. Did you not study heat in freshman physics?

I don't think I studied it enough..

So if the specific heat of water is 4.187 x 10^3 J/(kg * k )

That means it requires 4.187 x 10^3 J to raise 1 kg of water by 1 kelvin, correct?
 
Rijad Hadzic said:
I'm not sure actually.. this chapter that I'm studying is called Current and Resistance..

It has to do with specific heat, right? Also, does heat = thermal energy?
Yes, heat = thermal energy. To raise a kg water 1°C, you need 4184 Joules of heat (thermal energy).

http://www.kentchemistry.com/links/Energy/SpecificHeat.htm
 
What is the mass in kg of 40 gallons of water?
 
Last edited:
Chestermiller said:
What is the mass in kg of 40 gallons of water?

I think the asker had the converted number already [emoji846]. They wrote 151 kg.
 
Anyhow, using the heat you can now calculate the power (J/s). See that the heat is the 'J' and the time you have the 's'.

Now think about how you can get current!
 
Back
Top