Resolving forces in the direction perpendicular to a line

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Homework Help Overview

The discussion revolves around resolving forces in the direction perpendicular to a line, specifically focusing on two forces, F1 and F2. Participants are exploring the geometric relationships and trigonometric principles involved in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to identify the appropriate triangle to sketch for resolving the components of forces. Some participants question the specific components of force F1 and emphasize the importance of considering forces perpendicular to the lever arms.

Discussion Status

The discussion includes attempts to clarify the problem setup and explore different approaches to resolving the forces. One participant reports success in finding the answer by sketching triangles and applying trigonometric principles, indicating some productive direction in the conversation.

Contextual Notes

Participants are operating under the constraints of homework rules, which may limit the extent of guidance provided. There is an emphasis on understanding the geometric and trigonometric relationships without providing direct solutions.

Bolter
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Homework Statement
See below
Relevant Equations
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Hi I'm very stuck on what to do for these 2 questions I got wrong

Screenshot 2020-10-16 at 12.17.44.png

Screenshot 2020-10-16 at 12.17.56.png


Can someone please help me on what triangle I need to sketch out in order to find the 2 components of forces for F1 and F2. I'm assuming you have to make use of the sine or cosine rule here

I'd be grateful for any help given! Thanks
 
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What have you done so far?
Remember that what counts here are the actual forces that are perpendicular to the levers, all respect to the fulcrum A.
 
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What are the horizontal and vertical components of force F1?
 
I actually managed to find the right answer at the end by drawing triangles and labelling the forces that are perpendicular to the line AB. Then with some basic trig I got the force needed
 
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