Engineering RL Circuit Charging: The Effects of Closing the Switch on Inductor Charge

AI Thread Summary
When the switch in an RL circuit closes, the inductor does not charge but rather sustains and increases its current. Initially, the inductor maintains a constant current while the switch is open. Upon closing the switch, the inductor's current begins to rise, ultimately reaching four times its previous value. This behavior illustrates that inductors respond to changes in current rather than holding a charge. Understanding this principle is crucial for analyzing RL circuit dynamics.
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What happens when the switch closes? Does the inductor continue to charge? If yes, how can this be so when the inductor is already fully charged (the question says the switch was open for a long time, so I assumed it has been fully charged)?
 
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First, an inductor does not 'charge'. It sustains a current.

Before the switch closes the inductor sustains a certain constant current. When the switch closes the inductor current will start to sustain a larger current. Eventually it will sustain 4 times as much current as before the switch was closed.
 

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