Engineering RLC Circuit Second Order Differential and Laplace

AI Thread Summary
The discussion focuses on deriving a second-order differential equation for an RLC circuit and using the Laplace transform to express the total response as the sum of zero input and zero state responses. The equations derived from two loops include relationships between current, resistance, capacitance, and inductance. There is a noted confusion regarding the direction of current through the capacitor and its impact on the equations, particularly in relation to the load resistor. The correction emphasizes that the current through the load resistor should be negative if it flows counterclockwise. The thread highlights the importance of accurately defining current directions to avoid errors in circuit analysis.
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Homework Statement


Derive the second order differential equation relating x(t) and y(t).
Using the Laplace transform, find the total response as a function of the zero input response and the zero state response in the following form.

Homework Equations



Y(s)=Yzs(s) + Yzi(s)

The Attempt at a Solution



Loop1: Rs*i1 + 1/c integral(i1 + i2) dt = xs(t)

Loop2: 1/c integral(i1 + i2) dtau + Rload*i2 + L di2/dt = 0

Take derivatives

Loop1: R di1/dt + (i1 + i2)/C = dx/dt

Loop2: R di2/dt + L di2/dt + (i1 + i2)/C = 0
 

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Try solving for i1 in the second equation and substitute into the first equation. Then use y(t)=Rloadi2 to rewrite the equation in terms of y(t).
 
Loop2: 1/c integral(i1 + i2) dtau + Rload*i2 + L di2/dt = 0

I believe there is an error here. If the current through the capacitor is i1 + i2, then i2 is moving counterclockwise, and we know as the current approaches the load resistor, it is approaching the negative end of y(t). Therefore, Rload*i2 should be negative. I haven't checked everything, so there could be more problems.
 
I think that equation is fine; it's correct if you assume i2 goes in the counterclockwise direction. But I should have said to use y(t)=-Rloadi2. I forgot the OP used the opposite direction than usual on i2.
 

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