Calculating Initial Height for Marble to Roll Along Loop-the-Loop Track

In summary, this conversation discusses a problem involving a small solid marble rolling without slipping along a loop-the-loop track. The main question is at what initial height the marble must be released from the straight section of track so that it is on the verge of leaving the track. The problem can be solved using conservation of energy or Newton's 2nd law. The rotation of the marble about its horizontal axis does not affect its motion in the coordinate system of the loop. Another way to conceptualize this problem is to think of a roller coaster on a smooth track, where the height it needs to start at in order to make it through the loop is the same as the initial height of the marble.
  • #1
suspenc3
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A small solid marble of mass m and radius r will roll without slipping along A loop-the-loop track, if it was released from rest somewhere on the straight section of track from what initial height h above the bottom of the track must the marble be released so that it is on the verge of leaving the track? (the radius of the loop-the-loop is R)

Also assumes the marbles radius << loops radius

Ive seen problems like this in conservation of energy..whats the difference campared to this?
 
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  • #2
It is a conservation of energy problem. You have two kinds of kenetic energy to resolve when dealing with a rolling sphere. "I" know, but do you know?
 
  • #3
This problem can be solved with conservation of energy, but it doesn't have to be. So the relation to conservation of energy problem is that it is one.

You could also do it fairly easily with Newton's 2nd as well.

Also, there is only one kinetic energy. Do you mean that there is another component of kinetic energy because the ball is rotating about its horizontal axis? Doesn't matter. The rotation is about the centre of mass of the marble, and for a sphere of uniforn density it is at the centre of the sphere. So the rotation of a point on the surface of the sphere has nothing to do with the motion of the centre of mass of the sphere in the co-ordinate system of the loop.

how i saw this problem was: a roller coaster on a smooth track is elevated to some height, realeased and goes through the loop. How high does it need to be when it starts in order to make it through the loop..
 

What is the equation for calculating the initial height for a marble to roll along a loop-the-loop track?

The equation for calculating the initial height for a marble to roll along a loop-the-loop track is: h = r + (v^2 / 2g), where h is the initial height, r is the radius of the loop, v is the velocity of the marble, and g is the acceleration due to gravity.

What are the units for the variables in the equation?

The units for the variables in the equation are: h (meters), r (meters), v (meters per second), and g (meters per second squared).

How do you determine the radius of the loop in the equation?

The radius of the loop can be determined by measuring the distance from the middle of the loop to the highest point of the track where the marble will start. This will be the value for r in the equation.

What is the significance of the velocity in the equation?

The velocity of the marble is important because it determines the amount of kinetic energy the marble has at the top of the loop. This energy is needed to keep the marble moving along the track and prevent it from falling off.

Is there a minimum velocity required for the marble to successfully complete the loop-the-loop track?

Yes, there is a minimum velocity required for the marble to successfully complete the loop-the-loop track. This minimum velocity can be calculated by rearranging the equation to solve for v and setting the initial height to 0. The resulting equation is: v = √(2gh), where h is the height of the loop. This means that the marble must have a velocity of at least √(2gh) to successfully complete the loop-the-loop track.

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